A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
1 answer:
Answer:
There is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean is:
The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.
Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.
The 95% confidence interval for the average height of male students at a large college is, (63.5 inches, 74.4 inches).
The 95% confidence interval for the average height of male students (63.5, 74.4) implies that, there is a 0.95 probability that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Or, there is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
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Answer:
(a) NULL HYPOTHESIS, :
3.5%
ALTERNATE HYPOTHESIS, :
> 3.5%
(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.
Step-by-step explanation:
We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.
We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.
(a) Let, NULL HYPOTHESIS, :
3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}
ALTERNATE HYPOTHESIS, :
> 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}
The test statistics that will be used here is One-sample t-test;
T.S. = ~
where, = sample mean debt ratio of Ohio banks = 6%
s = sample standard deviation = = 1.83%
n = sample of banks = 7
So, test statistics = ~
= 3.614
(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.
Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.
Hence, Federal banking officials claim was correct.