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loris [4]
3 years ago
5

A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s

ample of 40 male students from the baseball team. Using this data, the doctor calculate the 95% confidence interval (63.5, 74.4).
Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

There is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.

Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the average height of male students at a large college is, (63.5 inches, 74.4 inches).

The 95% confidence interval for the average height of male students (63.5, 74.4) implies that, there is a 0.95 probability that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

Or, there is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).

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Which is the correct form of q(x) + r(x)/b(x) for expression 7x^4+x+14/x+2
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<span>(7x^4+x+14)/(x+2)
</span>(7x^4+x+14)----------------------|(x+2)
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<span>
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then
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