I assume your question amounts to finding the period of f(t)=8sin(4 pi t). A period L is a positive number such that f(t+L)=f(t) for all t. Since sin(x) is 2 pi perodic we can find the least number L such that 4pi(t+L)=4*pi*t+2*pi. Multiplying out we get
4pi(t+L)=4*pi*t+4*pi*L and we want to find L such that we get 4*pi*t+2*pi, notice if we take L=1/2 we get the desiered result 4*pi*t+4*pi*1/2=4*pi*t+2*pi. This proves that L=1/2 and your function has a period of 1/2.
Answer:
B) 4.8*10^2
Step-by-step explanation:
We are to find the dot product of the given vectors. To find this just multiply the coefficients of i terms(horizontal components) and multiply the coefficients of j terms(vertical components), and add the two products together, as shown below:
a.b = (6i + 5j).(-5i+4j)
a.b = 6(-5)+5(4)
a.b = -30 + 20
a.b = -10
The dot product results in a scalar quantity, so you only get a magnitude not a vector.
The answer is 3/4 and it was already simplified
Answer:
a=2 and b=2...............
