All categories

4 years ago

How do I find and mean within the data set?

Mathematics

1 answer:

kvv77 [185]4 years ago

7 0

The mean is like the average. you would add up all the numbers and divide by the amount of numbers there are. in this case, add them all up and divide by 6 because there are 6 different numbers. this will give you your answer

You might be interested in

Can you please explain ME how to solve identity of algebra homework

yKpoI14uk [10]

Step-by-step explanation:

"identity" means an operation that does nothing.

For adding numbers, adding 0 changes nothing, so 0 is the identity for addition.

For multiplication, multiplying by 1 changes nothing, so 1 is the identity for multiplication.

3 0

3 years ago

Statistics question about random probability Cheese pastureized or Raw MilkA cheese can be classified as either raw-milk or past

blsea [12.9K]

Answer:

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) Or Pr(RRPP) Or Pr(RRRP) Or Pr(RRRR)

= 0.1269 to 4 decimal places

It would not be unusual that at least one of four randomly selected cheeses is raw-milk, because the probability have a value between 0 and 1

Step-by-step explanation:

If is given that 80% of the cheese is classified as pasteurized.

It then implies that 20% of the cheese is classified as Raw-milk

Probability of pasteurized cheese is 0.82(Denoted by Pr(P))

Probability of raw-milk cheese is 0.18(Denoted as Pr(R))

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) + Pr(RRPP) + Pr(RRRP) + Pr(RRRR)

(0.18 x 0.82 x 0.82 x 0.82) + (0.18 x 0.18 x 0.82 x 0.82) + (0.18 x 0.18 x 0.18 x 0.82) + (0.18 x 0.18 x 0.18 x 0.18) = 0.1269 to 4 decimal places

3 0

3 years ago

How many different ways can you make 82 cents using current u.s. currency

andrew11 [14]

<span>You can probably just work it out.

You need non-negative integer solutions to p+5n+10d+25q = 82.

If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80.

So this is the same as n + 2d + 5q ≤ 16

So now you simply have to "crank out" the cases.

Case q=0 [ n + 2d ≤ 16 ]

Case (q=0,d=0) → n = 0 through 16 [17 possibilities]
Case (q=0,d=1) → n = 0 through 14 [15 possibilities]
...
Case (q=0,d=7) → n = 0 through 2 [3 possibilities]
Case (q=0,d=8) → n = 0 [1 possibility]

Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81

Case q=1 [ n + 2d ≤ 11 ]
Case (q=1,d=0) → n = 0 through 11 [12]
Case (q=1,d=1) → n = 0 through 9 [10]
...
Case (q=1,d=5) → n = 0 through 1 [2]

Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42

Case q=2 [ n + 2 ≤ 6 ]
Case (q=2,d=0) → n = 0 through 6 [7]
Case (q=2,d=1) → n = 0 through 4 [5]
Case (q=2,d=2) → n = 0 through 2 [3]
Case (q=2,d=3) → n = 0 [1]

Total from case q=2: 1 + 3 + 5 + 7 = 16

Case q=3 [ n + 2d ≤ 1 ]
Here d must be 0, so there is only the case:
Case (q=3,d=0) → n = 0 through 1 [2]

So the case q=3 only has 2.

Grand total: 2 + 16 + 42 + 81 = 141 </span>

3 0

3 years ago

sally's $1800 savings is in two accounts.Her total interest for the year was $93 from one account earning 6% interest and anothe

myrzilka [38]

Answer:

$500 invested at 3%

$1300 invested at 6%

Step-by-step explanation:

8 0

4 years ago

Brand A has a recognition value worth 43 billion more than brand B if the total value of these two brands is 111billion find the

saveliy_v [14]

Answer:

68 and 43 are the answer

6 0

3 years ago