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wolverine [178]
3 years ago
15

Find the volume of a pyramid with a square base, where the side length of the base is 7.5 cm and the height of the pyramid is 10

.2. Round your answer to the nearest tenth of a cubic centimeter
Mathematics
1 answer:
m_a_m_a [10]3 years ago
8 0

Answer:

The volume  is  191.3 cm^3

Step-by-step explanation:

Recall that the formula for the volume of a pyramid is given by the formula:

Volume=\frac{B\,*H}{3}

where B is the area of the pyramid's base, and H its height. So, in our case, the base is a square of length 7.5 cm, which gives 56.25 cm^2

Now, we use this value and the height 10.2 cm to find the volume:

Volume=\frac{B\,*H}{3}\\Volume=\frac{56.25\,*10.2}{3}\\Volume=191.25\,\,cm^3

which rounded to the nearest tenth is: 191.3 cm^3

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AURORKA [14]

Given :

  • -3x² - 9x + 12 = 0

To find :-

  • Value of x .

Solution :-

Given equation ,

  • -( 3x² + 9x -12 ) = 0
  • 3x² + 9x - 12 = 0
  • 3x² + 12x - 3x - 12 = 0
  • 3x ( x +4) -3( x +4) = 0
  • (3x -3)(x +4) = 0
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7 0
3 years ago
Using the functions presented in the example, how much can Cam expect to earn if he sells all the corn produced on 1.5 acres?
12345 [234]

Answer:

Cam expect to earn if he sells all the corn produced on 1.5 acres is $8725.

Step-by-step explanation:

Given : C(a)=7500a-1500, M(C)=0.9C- 50  and  M(C(a))=6750a-1400

To find : How much can Cam expect to earn if he sells all the corn produced on 1.5 acres?

Solution :  

C(a)=7500a-1500

Substitute a=1.5,

C(1.5)=7500(1.5)-1500

C(1.5)=11250-1500

C(1.5)=9750

Now, taking function M(C)=0.9C- 50

Substitute C=9750,

M(9750)=0.9(9750)- 50

M(9750)=8775- 50

M(9750)=8725

Now, taking function M(C(a))=6750a-1400

Substitute a=1.5,

M(C(1.5))=6750(1.5)-1400

M(C(1.5))=10125-1400

M(C(1.5))=8725

Therefore, Cam expect to earn if he sells all the corn produced on 1.5 acres is $8725.

8 0
3 years ago
The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle​
AVprozaik [17]

Answer:

  • Length of rectangle is 31 yards and Width is 24 yards.

Given:

  • The length of a rectangle is 7 more than the width.
  • The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

\\  \:  \:  \:  \:  \pink{ \dashrightarrow \:  \:  \:  \:  \sf { \underbrace{Area_{(Rectangle)} =  Length × Width  }}} \\  \\

On Substituting the required values, we get;

\\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 7x = 744 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 7x - 744 = 0 \\ \\ \\  \: \: \: \:  \dashrightarrow \: \: \: \: \sf  {x}^{2}  + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \:  \dashrightarrow \: \: \: \: \sf x = 24 \:  or \:   - 31 \\ \\

As we know that width of the rectangle can't be negative. So x = 24

<u>Hence</u>,

  • Width of rectangle = x = 24 yards
  • Length of the rectangle = x + 7 = 31 yards

\thereforeLength of rectangle is 31 yards<u> </u>and Width is 24 yards.

8 0
2 years ago
A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes
bekas [8.4K]

Answer:  1) 1/3,654     2) 3/406     3) 72,684,900,288,000      4) 120

<u>Step-by-step explanation:</u>

1)         First       and        Second         and         Third

  \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}

2)         First       and          Second

   \dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}

3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}

4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}

8 0
3 years ago
Help please? thank you
Alexxandr [17]

9514 1404 393

Answer:

  RS = √(b² +(c -a)²)

Step-by-step explanation:

Put the given point coordinates in the given formula:

  • R = (x₁, y₁) = (0, a)
  • S = (x₂, y₂) = (b, c)

  RS = √((b -0)² +(c -a)²)

  RS = √(b² +(c -a)²)

8 0
2 years ago
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