Answer:
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.7787.
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.9 - 3.7 = 1.2.
The upper end of the interval is the sample mean added to M. So it is 4.9 + 3.7 = 8.6.
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
M=c•p
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We have to answer what does the 15 represent in the function : f ( x ) = 15 * 2^x, which models the increasing of the frog population at a lake. We know that the frog population doubles every 3 weeks and that: f ( 6 ) = 960. It means that: 15 * 2^ 6 = 15 * 64 = 960. And also f ( 0 ) = 15 * 2^0 = 15 * 1 = 15. Therefore it is a starting population. Answer: The 15 represents <span>B - The starting population.</span>
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