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scoundrel [369]
3 years ago
7

Simplify 7N - 2N + 3P + 2P. 5N + 5P 10N + 10P 10NP

Mathematics
1 answer:
Pepsi [2]3 years ago
8 0

Answer:

5n+5p

Step-by-step explanation:

7n-2n+3p+2p

5n+5p (combine like terms)

the answer is 5n+5p

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Find two consecutive odd integers whose product is 1443
liberstina [14]

Let's x represents the first odd integer

The next consecutive integer would be represented as x+2.

So x and x+2 being multiplied together will give us 1443:

(x)(x+2)=1443

x^2+2x=1443

x^2+2x-1443=0

By solving the quadratic equation using the quadratic formula, x will equal to 37 and -39.

Since the problem says "integers", so I'm assuming two pairs of consecutive integers would be ok.

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6 0
3 years ago
Find a value for y for which the expression (1-y)(3-y)(6-y) has each given value
erik [133]

\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=-70

\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=-70

\\ \tt\Rrightarrow y(2)(4)(7)=70

\\ \tt\Rrightarrow y(56)=70

\\ \tt\Rrightarrow y=\dfrac{70}{56}

\\ \tt\Rrightarrow y=\dfrac{5}{4}

#2

\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=120

\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=120

\\ \tt\Rrightarrow -y(2)(4)(7)=120

\\ \tt\Rrightarrow 56y=-120

\\ \tt\Rrightarrow y=\dfrac{-120}{56}

\\ \tt\Rrightarrow y=\dfrac{-15}{7}

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3 years ago
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