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Rina8888 [55]
3 years ago
8

Translate and solve: −5 times b is no less than −35.

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

-3\leq \\2n-5\leq15

Step-by-step explanation:

  • 2n-5 at least -3, at most 15
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zhannawk [14.2K]

Answer:

1) pounds

2) grams

3) tons

Step-by-step explanation:

The suitable measurements for the scenarios are:

1) A piano weighs 5.5 × 10² units

  550 Ib (pounds)

2) A grain of salt weighs 1.02 × 10^-3  units

    0.00102 grams

3) A tractor trailer weighs 8.8 × 10^1 units

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10²g = 1kg

10^-3g = miligrams

10^1 g = decagram

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Select all the stories that can be represented by the diagram.
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Answer: Choice C and Choice D

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Explanation:

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  • Choice C does work. If x is the number of grapes Noah gives each friend, then 3x is the total amount Noah gives over. Then 3x+1 is the number of grapes total. That +1 at the end is the grape Noah eats. We end up with 3x+1 = 7 because Noah starts off with 7 grapes.
  • Choice D works also. The x is the number of hours for math, science and history each. So 3x is the combined time of those three classes. Add on 1 to get 3x+1 to represent all 7 hours, ie 3x+1 = 7.
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What is the slope of the line represented by the values in the table?
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The slope would be 2. Rise over run remember that.
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After being hit, the puck travels along the ice at a constant speed. What might cause his motion to change?
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Step-by-step explanation:

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7 0
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Find the simplified product b-5/2b x b^2+3b/b-5
White raven [17]

Answer:

The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

=bb+3b=b(b+3)

=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

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3 years ago
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