The slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
<h3>How to find the slope of a line?</h3>
given that the equation is 5x - 3y = 2.
now write the equation in standard form y = mx + b
then -3y = 2 - 5x
y = -2/3 + 5x/3
y = 5/3x - 2/3
m 1*m 2 = - 1 is the formula for the slopes from a pair of perpendicular lines. where the slopes of the lines are m 1 and m 2.
Here m1 = 5/3 and m2 = -3/5.
Hence,the slope of a line perpendicular to the
graph of the equation 5x - 3y = 2 is -3/5.
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The missing step in this proof is ∠BAC ≅ ∠BDE ⇒ answer D
Step-by-step explanation:
If two triangles are similar by SAS, then their corresponding angles are
equal and the 3rd corresponding sides have constant ratio
In the two triangles ABC and DBE:
- ∠ABC ≅ ∠DBE

Then the two triangles are similar
From similarity:
∠BAC ≅ ∠BDE
∠BCA ≅ ∠BED
∴ The missing step is ∠BAC ≅ ∠BDE
The missing step in this proof is ∠BAC ≅ ∠BDE
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Here are the scores of students on a history test. 57,58,61,61,65,71,73,75,77,78,80,82,92 Notice that the scores are ordered fro
trasher [3.6K]
I hope this helps the five numbers on the bottom 71 7374 7577 is the interquartile range