Answer:
Step-by-step explanation:
Given that a group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below.
Data set is as ollows:
70 79 38 63 44 23 62 61 67 50 61 70 94 87 65
H0: mu = 60 sec
Ha: mu not equals 60 sec
Mean diff = 2.27
Test statistic = 2.27/SE =0.4815
p value =0.6376
Since p>0.05, we accept null hypothesis
i.e. there is statistical evidence to say that students are reasonably good at estimating one minute