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3 years ago

QUICKLY PLEASE

Mathematics

2 answers:

KengaRu [80]3 years ago

6 0

Answer:

1 and 5. First and the last one

Step-by-step explanation:

i just took the ed test.

dangina [55]3 years ago

6 0

Answer:

1st and 5th

Step-by-step explanation:

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This week, Jamyra spent a total of 100 minutes studying. This total was 8 more than four

Harrizon [31]

Answer:

Jamyra spent 23 minutes studying last week.

Step-by-step explanation:

100 - 8 = 92

92 ÷ 4 = 23.

7 0

3 years ago

I don’t get this please help ASAP

jek_recluse [69]

Answer:

AE = 70

Step-by-step explanation:

Given that ACE is a triangle and B , D , F are mid-points of AC, CE, AE respectively.

⇒ BF, FD, BD are mid-segments.

Mid-segment is a line segment joining mid points of two sides of a triangle,

And it as two properties :

1) mid-segment is always parallel to the third side

2) mid-segment is half in length of the third side

⇒ Here, BD is the mid-segment and is parallel to third side AE

And also BD is half of AE

⇒ AE = 2×BD = 2×35

⇒ AE = 70.

3 0

3 years ago

Kristen reads 11 pages per hour. In all, how many hours of reading will Kristen have to do

soldier1979 [14.2K]

Answer:

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just don’t want to waste my time in case you don’t want me to :)

6 0

3 years ago

Help fast pleaseee<br> NO RANDOMS

Nezavi [6.7K]

Answers:
a. -80
b. -60
c. 98
d. -54

5 0

2 years ago

Read 2 more answers

I rlly need help with this :(

kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 72.6, \sigma = 2.7$ .

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{74.2 - 72.6}{2.7}$

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{78 - 72.6}{2.7}$

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{70 - 72.6}{2.7}$

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0

2 years ago