Answer:
What other information does Jada need to communicate about this sequence of transformations
Step-by-step explanation:
1/9 because i you plug in two of the points into y2 -y1 over x2 -x1 thats what you get.
Answer:The value of the bulldozer after 3 years is $121950
Step-by-step explanation:
We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as
Annual depreciation expense =
(Cost of the asset - salvage value)/useful life of the asset.
From the given information,
Useful life = 23 years
Salvage value of the bulldozer = $14950
Cost of the new bulldozer is $138000
Therefore
Annual depreciation = (138000 - 14950)/ 23 = $5350
The value of the bulldozer at any point would be V. Therefore
5350 = (138000 - V)/ t
5350t = 138000 - V
V = 138000 - 5350t
The value of the bulldozer after 3 years would be
V = 138000 - 5350×3 = $121950
Answer:
10 times greater
Step-by-step explanation:
Because value of 5 in 503 is 5*100
Then the value of 5 in 53 is 5*10
So then value of 5 in 503 is 10 times greater than the value of 5 in 53
I hope this helps
Answer:
I'm not sure the answer to this
