Switch\:sides
-9s<-72
\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}
\left(-9s\right)\left(-1\right)>\left(-72\right)\left(-1\right)
\mathrm{Simplify}
9s>72
\mathrm{Divide\:both\:sides\:by\:}9
\frac{9s}{9}>\frac{72}{9}
Simplify
s > 8
Yes because all sides are equal so take one side and multiply by it by 3 and thats ur anwaserr
Answer:
sin 3 θ = 3 sin θ - 4 sin³θ
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given sin 3 θ
= sin ( 2θ + θ )
apply trigonometric formula
<em> sin ( A + B) = sin A cos B + cos A sin B </em>
<em> sin 2 A = 2 sin A cos B</em>
<em> Cos 2 A = 1 - 2 sin² A </em>
<em> cos ² A - sin ² A = 1</em>
<u><em>Step(ii):</em></u>-
sin 3 θ = sin ( 2θ + θ )
= sin 2θ cosθ + cos2θ sin θ
= 2 sin θ cos θ cos θ +( 1 - 2 sin² θ )sin θ
= 2 sin θ (cos² θ ) + sin θ- 2 sin³ θ
= 2 sin θ ( 1- sin²θ) + sin θ- 2 sin³ θ
= 2 sin θ - 2sin³θ + sin θ- 2 sin³ θ
= 3 sin θ - 4 sin³θ
<u><em>Final answer</em></u> :-
sin 3 θ = 3 sin θ - 4 sin³θ
Hello, I believe the answer you’re looking for is beyond my ability thank you but 10+10=20 yessir
