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3 years ago

The valume of (3-5)4(2)-16+2

Mathematics

1 answer:

rusak2 [61]3 years ago

8 0

Answer:

-30

Step-by-step explanation:

Calculate the difference:

(3-5)x4x2- 16 plus 2

Result: -2x4x2- 16 plus 2

calculate the product...

Result: -16-16 plus 2

Calculate the sum or difference

ANSWER: -30

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You want to save $500 for a school trip. You begin by saving a penny on the first day. You save an additional penny each day aft

irga5000 [103]

Answer:

Step-by-step explanation:

The formula for determining the sum of n terms of an arithmetic sequence is expressed as

Sn = n/2[2a + (n - 1)d]

Where

n represents the number of terms in the arithmetic sequence.

d represents the common difference of the terms in the arithmetic sequence.

a represents the first term of the arithmetic sequence.

From the information given,

a = 1 penny = 1/100 = $0.01

d = 0.01

a) For 100 days, the sum of the first 100 terms, S100 would be

S100 = 100/2[2 × 0.01 + (100 - 1)0.01]

S100 = 50[0.02 + 0.99)

S100 = 50 × 1.01 = $50.5

b) when Sn = $500, then

500 = n/2[2 × 0.01 + (n - 1)0.01]

Multiplying through by 2, it becomes

500 × 2 = n[2 × 0.01 + (n - 1)0.01]

1000 = n[0.02 + 0.01n - 0.01]

1000 = n[0.01 + 0.01n]

1000 = 0.01n + 0.01n²

0.01n² + 0.01n - 1000 = 0

Applying the general formula for quadratic equations,

x = [-b±√(b² - 4ac)]/2a

n = - 0.01±√0.01²-4(0.01 × - 1000)]/2 × 0.01

n = (- 0.01 ± √40.001)/0.02

n = (- 0.01 + 6.32)/0.02 or

n = (- 0.01 - 6.32)/0.02

n = 315.5 or n = - 316.5

Since n cannot be negative, then n = 315.5

It will take approximately 316 days to save $500

6 0

3 years ago

Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K

zalisa [80]

<h2>Hello!</h2>

The answer is:

It will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

To calculate how long after they start they will be 3/4 miles apart, we need to write two equations.

So, writing the equations, we have:

Calculations for Ava:

We have the following information,

$v_{Ava}=6mph$

Then, writing the equation,

$x_{Ava}=x_{o}+v_{Ava}*t$

$x_{Ava}=x_{o}+v_{6mph}*t$

Calculations for Kelly:

We have the following information,

$v_{Kelly}=8mph$

We need to calculate when Kelly will be 3/4 miles apart of Ava, so, it's position will be the Ava's position plus 3/4 miles.

Then, writing the equation,

$x_{Ava}+0.75miles=x_{o}+v_{Kelly}*t$

$x_{Ava}+0.75miles=x_{o}+v_{8mph}*t$

Now, substituting Ava's speed into the second equation, we have:

$x_{o}+6mph*t+0.75miles=x_{o}+8mph*t$

$6mph*t+0.75miles=+8mph*t$

$8mph*t-6mph*t=0.75miles$

$2mph*t=0.75miles$

$t=\frac{0.75miles}{2mph}=0.375hours$

Hence, we have that it will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

Have a nice day!

7 0

3 years ago

Read 2 more answers

What is the measure of the base in the triangle below?

lesantik [10]

Step-by-step explanation:

AC+CB+BA=180

2x+23+3x-8+4x+1=180

9x+16=180

9x=180-16

9x=164

x=164/9

x=18.2

5 0

2 years ago

a lever will balance if the mass of object 1 times its distance from the fulcrum equals the ma's of object 2 times its distance

Afina-wow [57]

If the distance between the fulcrum and the effort is increased, the distance that the effort must move the lever increases as well. Conversely, if the distance between the fulcrum and the load is decreased, the distance that the lever must move also decreases.

so we have too apply more force to pull the lever cause the distance is 1x smaller then mia lever so on mia lever we ull moree to get it to move!

4 0

3 years ago

Please help me thanks

drek231 [11]

6in×2=12inches and 2/5×2=0.8 so the answer would be 12.8

6 0

3 years ago