Using the definition of expected value, it is found that Ayo can be expected to make a profit of £55.8.
The <em>expected value</em> is given by the <u>sum of each outcome multiplied by it's respective probability.</u>
In this problem:
- The player wins $6, that is, Ayo loses £6, if he rolls a 6 and spins a 1, hence the probability is
.
- The player wins $3, that is, Ayo loses £3, if he rolls a 3 on at least one of the spinner or the dice, hence, considering three cases(both and either the spinner of the dice), the probability is

- In the other cases, Ayo wins £1.40, with
probability.
Hence, his expected profit for a single game is:

For 216 games, the expected value is:

Ayo can be expected to make a profit of £55.8.
To learn more about expected value, you can take a look at brainly.com/question/24855677
The formula for volume is
... V = Bh . . . . . where B is the area of the base, and h is the height
You have
... 18/35 = 2/5·h
... 18/35·5/2 = h = 9/7
The height is 9/7 units.
5 x (10^2) =
5 x 100 = 500
I guess you mean:
4,5 x (10^2) =
4,5 x 100 =
450
Which acctually is a valid answer.
Use this formula.
and solution is:[(18!)/(6!×(18-6)!)]×(1/2)^6×(1-1/2)^(18-6)≈0.0781604
7.8%
Answer:
178 ERASERS
Step-by-step explanation:
YOU NEED TO START BACKWARDS. HE BOUGHT 76 ERASERS AND HE HAS 193, SO WHATEVER HE HAD AT THE END OF TUESDAY+76 IS HOW MUCH HE HAS ON WEDNESDAY. 193-76=117. ON TUESDAY, HE STARTED WITH ERASERS AT END OF TUESDAY+39 ERASERS. 117+39=156. ON MONDAY, HE STARTED WITH END OF MONDAY+22 ERASERS. 156+22=178