Length=3width-5
(2(x))+(2(3x-5)=46
2x+6x+10=46
8x=56
x=7
width=7 length=16
Answer:
I'm pretty sure it's both, but I can see this is a summative exam/test so I'm really sorry if it's wrong.
If Yoshi has 8 per pack and used 7 he would have 32 markers in all and bought 3 packs and had an extra marker
The true one
miguel save 60$ on 4 months
The false one
After 2 months miguel has 20$
The sum of any geometric sequence, (technically any finite set is a sequence, series are infinite) can be expressed as:
s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=term number
Here you are given a=10 and r=1/5 so your equation is:
s(n)=10(1-(1/5)^n)/(1-1/5) let's simplify this a bit:
s(n)=10(1-(1/5)^n)/(4/5)
s(n)=12.5(1-(1/5)^n) so the sum of the first 5 terms is:
s(5)=12.5(1-(1/5)^5)
s(5)=12.496
as an improper fraction:
(125/10)(3124/3125)
390500/31240
1775/142
