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3 years ago

11

An object placed between two plane mirrors arranged at right angles to each other at a distance d1 from the surface of one mirro

r and a distance d2 from the surface of the other. How many images are formed?
2

3

1

0

1 answer:

balu736 [363]3 years ago

3 0

Answer:

3

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a force of 45 N isvexerted on an object, resulting in an acceleration of 5 m/s^2 for the object what will the objects accelerati

ki77a [65]

Answer:

the acceleration will be 10 m/s^2

Explanation:

the force applied to an object and the acceleration of the object are directly proportional, as Newton's second law states:

$F=ma$

where

F is the net force applied to the object

m is the object's mass

a is the object's acceleration

in the first example, a force F=45 N is applied to the object, giving it an acceleration of a=5 m/s^2. Therefore, the mass of the object is

$m=\frac{F}{a}=\frac{45 N}{5 m/s^2}=9 kg$

In the second example, the force is doubled, so it will be F=90 N. The mass is still m=9 kg, so the acceleration will be

$a=\frac{F}{m}=\frac{90 N}{9 kg}=10 m/s^2$

8 0

3 years ago

What is the change in length of a 1400. m steel, (12x10^-6)/(C0) , pipe for a temperature change of 250.0 degrees Celsius? Remem

8090 [49]

Answer:

$\Delta L = 4.2 m$

Explanation:

As per the formula of thermal expansion we know that

$L = L_o(1 + \alpha\Delta T)$

so here we will have

$L_o = 1400 m$

$\alpha = 12 \times 10^{-6} per ^oC$

$\Delta T = 250 degree C$

so here change in the length of the rod is given as

$\Delta L = L - L_o$

$\Delta L = L_o \alpha \Delta T$

$\Delta L = 1400 (12 \times 10^{-6})(250)$

$\Delta L = 4.2 m$

8 0

4 years ago

A train travels 72 kilometers in 1 hours, and then 64 kilometers in 1 hours. What is its average speed?

garri49 [273]

To find the average of something you must first add everything together and then divide it by the total amount of numbers you added together.

First add 72 and 64 together

72+64=136

Now divide 136 by 2

136/2=68

So the average speed of the train is 68 kilometers

5 0

3 years ago

Where would a Christmas tree be most likely to grow?

sveticcg [70]

Taiga is the answer.

Hope it helps!

3 0

3 years ago

An 870 N firefighter, F_ff, stands on a ladder that is 8.00 m long and has a weight of 355 N, F_ladder. The weight of the ladder

castortr0y [4]

Answer:

Explanation:

Weight of the ladder is 355N

WL = 355N

The weight of the ladder acts at center of the ladder I.e at 4m from the bottom

Weight of firefighters is 870N

Wf = 870N

The fire fighter is at 6.3m from the bottom of the ladder.

N1 is the normal force exerted by the wall

N2 is the normal force exerted by the ground

Using Newton law

Check attachment

ΣFy = 0, since body is in equilibrium

N₂ - WL - Wf = 0

N₂ = WL + Wf

N₂ = 870 + 355

N₂ = 1225 N

This the normal force exerted by the ground on the wall.

Now to get N₁, let take moment about point A

So, before we take the moment we need to make sure that the forces are perpendicular to the plane(ladder), we need to resolve the weight of the ladder, firefighter and the normal of the wall to be perpendicular to the plane.

ΣMa = 0

Clockwise moment is equal to anti-clockwise moment

Moment Is the produce of force and perpendicular distance.

M = F×r

So,

WL•Cos50 × 4 + Wf•Cos50 × 6.3 —N₁•Sin50 × 8 = 0

355•Cos50 × 4 + 870•Cos50 × 6.3 =

N₁•Sin50 × 8

1825.52 + 3523.12 = 6.13N₁

6.13N₁ = 5348.64

N₁ = 5348.64/6.13

N₁ = 872.54 N.

The normal force exerted by the wall is 872.54N

5 0

3 years ago