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svetlana [45]
3 years ago
10

Tricia puts 44 g of dry ice (solid CO2) into a 2.0-L container and seals the top. The dry ice turns to gas at room temperature (

20°C) Find the pressure increase in the 2.0-L container. (One mole of CO2 has a mass of 44 g, R = 0.0821 L×atm/molxK. Ignore the initial volume of the dry ice.)
A) 6 atm
B) 18 atm
C) 2 atm
D) 12 atm
Physics
1 answer:
Irina-Kira [14]3 years ago
6 0

Answer:

Corect answer is D

Explanation:

Assuming that the  C O 2  gas is behaving ideally, therefore, we can use the ideal gas law to find the pressure increase in the container by:

P V=nRT ⇒  P=n R T /V

n=no of moles of the gas = mass/molar mass

Molar mass o f  C O 2=44g/mol, mass = 44g

mole n = 1mole

T=20C=293K

R=0.0821L.atm/mol.K

P=nRT/V

P = 1 x 0.0821 x 293/2

P = 12atm

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You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
stellarik [79]

A) The change in internal chemical energy is 1.15\cdot 10^7 J

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

Learn more about power and energy:

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Given :

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Solution :

Since, refrigerator is moving with constant velocity.

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