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3 years ago

How many molecules do we have for Na2Co3?

Physics

1 answer:

-BARSIC- [3]3 years ago

8 0

105.9888 g/mol is the mass as far as i know, Don't know the amount of molecules tho.

mark me brainliestt :))

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VLD [36.1K]

Answer:

Option C

Explanation:

According to the formula

$\\ \boxed{\sf R=\rho\dfrac{\ell}{A}}$

If we use wide wire we increase the area of cross section so resistance decreases

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2 years ago

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pishuonlain [190]

Answer:

A) asteroid

Explanation:

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3 years ago

7. Many medicines started out as natural products.Penicillin was originally made from _______________

larisa [96]

B.Bark of a willow tree

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3 years ago

Read 2 more answers

What is the electric force acting between two charges of -0.0050 C and 0.0050 C that are 0.025 m apart?

nika2105 [10]

Answer:

(A) $-3.6\times 10^8\ N$

Explanation:

Given:

Charge of one particle (q₁) = -0.0050 C

Charge of another particle (q₂) = 0.0050 C

Separation between them (d) = 0.025 m

We know that, from Coulomb's law, electric force acting between two charged particles is given as:

$F_e=\dfrac{kq_1q_2}{d^2}\\\\Where,k\to Coulomb's\ constant = 9\times 10^9\ N\cdot m^2/C^2$

Plug in the given values and solve for electric force, $F_e$ . This gives,

$F_e=\frac{(9\times 10^9\ N\cdot m^2/C^2) (-0.0050\ C)(0.0050\ C)}{(0.025\ m)^2}\\\\F_e=\frac{-2.25\times 10^{-4}\times 10^9}{6.25\times 10^{-4}}\ N\\\\F_e=-3.6\times 10^8\ N$

Therefore, option (A) is correct. Negative sign implies that the nature of electric force is attraction.

3 0

3 years ago

The most energy-efficient way to send a spacecraft to the Moon is to boost its speed while it is in circular orbit about the Ear

jeyben [28]

Answer:

98.33 %

Explanation:

On an elliptical orbit, angular momentum will be conserved .

Angular momentum = I ω = mvR

So mv₁R₁ = mv₂R₂

= v₁R₁ = v₂R₂

where v₁ is velocity and R₁ radius in low orbit (perigee)and v₂ and R₂ is velocity and radius in high orbit ( apogee ).

Here R₁ = Radius of the earth , R₂ is distance between moon and earth.

R₁ / R₂ = 1/60

v₁ /v₂ = R₂ / R₁ = 60

v₂ / v₁ = 1 / 60

1 - (v₂ / v₁ ) = 1 -( 1 / 60)

(v₁ -v₂)/v₁ = ( 60-1 )/60

(v₁ -v₂)/v₁ x 100 = 5900/60 = 98.33 %

5 0

4 years ago