All categories

3 years ago

Does anyone know what goes into these blanks

Mathematics

1 answer:

avanturin [10]3 years ago

4 0

yes I know but will not give answer because you have not say that

You might be interested in

PLS help me Order four and seven tenths repeating, negative four and eight ninths, 490%, and −4.9 from least to greatest.

Digiron [165]

The order from least to greatest negative four and seven tenths repeating, negative four and eight ninths, 490%, and −4.9 from least to greatest is; option A

−4.9,
negative four and eight ninths
four and seven tenths repeating
490%,

<h3>Ascending order</h3>

four and seven tenths repeating

= 4.77777777

negative four and eight ninths

= -4 8/9

= -4.888888888888888

490%

= 490/100

= 4.9

−4.9

Rearranging from least to greatest (ascending order)

-4.9
-4.888888888888888
4.77777777
4.9

Learn more about ascending order;

brainly.com/question/12783355

#SPJ1

6 0

2 years ago

Find the area of the following rectangles. 5 7/8 km x 18/4 km

tamaranim1 [39]

<span> is the answer a Polygon</span>

7 0

3 years ago

Read 2 more answers

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$