Answer:
f(g(x)) = 2(x^2 + 2x)^2
f(g(x)) = 2x^4 + 8x^3 + 8x^2
Step-by-step explanation:
Given;
f(x) = 2x^2
g(x) = x^2 + 2x
To derive the expression for f(g(x)), we will substitute x in f(x) with g(x).
f(g(x)) = 2(g(x))^2
f(g(x)) = 2(x^2 + 2x)^2
Expanding the equation;
f(g(x)) = 2(x^2 + 2x)(x^2 + 2x)
f(g(x)) = 2(x^4 + 2x^3 + 2x^3 + 4x^2)
f(g(x)) = 2(x^4 + 4x^3 + 4x^2)
f(g(x)) = 2x^4 + 8x^3 + 8x^2
Hope this helps...
Answer:
We have 7 complete teams
Step-by-step explanation:
Here, we have students preparing to make a team of 8 students per team. We now want to know how many complete teams they can make if they are a total of 60;
To get this, we need the multiples of 8;
we have;
8, 16 , 24 , 32, 40 , 48 , 56
So breaking it in 8s, we have;
8 8 8 8 8 8 8
We have 7 8s;
So there would be four left overs
My answer was wrong, I'm am very sorry
The answer to this question is
Both Parabolas open to the right, and x= 3y2 is wider than x= 5y2.
(APEX)
