Ask question

Ask question

All categories

3 years ago

15

If the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of another right triangle, then the

right triangles are congruent.

1 answer:

tigry1 [53]3 years ago

6 0

Answer:

Yes, because according to the Pythagorean theorem a squared + b squared = c squared.

In simpler terms, triangles have to have at least 2 legs = to be congruent to each other.

Hope this helps :)

You might be interested in

Linear equation for (-5,3) and (-1,-1)

Alex787 [66]

Answer:

y = -x - 2

Step-by-step explanation:

y = mx + c

m = (-1-3)/(-1-(-5)) = -4/4 = -1

y = -x + c

(-1,-1)

-1 = -(-1) + c

c = -2

y = -x - 2

6 0

3 years ago

A square is cut from a rectangle. The side length of the square is half of the unknown width w. The area of the shaded region is

Virty [35]

Answer:

See below

Step-by-step explanation:

<u>The side of the square is w/2, then its area is:</u>

A = (w/2)² = w²/4

<u>The shaded area is the difference of areas of the rectangle and the square:</u>

14w - w²/4 = 84

<u>This can be simplified:</u>

56w - w² = 336
w² - 56w + 336 = 0

8 0

2 years ago

Add The Following Polynomials?

Mashcka [7]

(6x^3 + 4x-2) + (4x^2 + 3x^3 - 6)=
6x^3 + 4x-2 + 4x^2 + 3x^3 - 6=
9x^3+4x^2+4x-8

4 0

3 years ago

carbon-14 has a half-life of 5730 years. The formula f(t)=(1/2)^t/5730 give the percentage of carbon-14 left in the item after t

andreyandreev [35.5K]

Heyy sorry I need the points

5 0

3 years ago

Help<br><br> Determine which equation is parallel to line jk and which is perpendicular to line jk.

alukav5142 [94]

Answer:

5x + 3y = 13 parallel.

6x - 10y = 7 perpendicular.

Step-by-step explanation:

Two lines with slopes $m_1$ and $m_2$ are parallel when $m_1=m_2$ and are perpendicular when $m_1*m_2=-1$

Now determine the slope of all the lines

The line jk passes through the points

(-5,5) and (1,-5) so its slope is

$\frac{-5-5}{1-(-5)}=\frac{-10}{6}=-\frac{5}{3}$

To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope

5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3

Neither parallel nor perpendicular.

6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5

Neither parallel nor perpendicular.

5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3

This line is parallel

6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5

Since (-5/3)(3/5) = -1 this line is perpendicular.

8 0

3 years ago