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3 years ago

Six PRODUCT Identities involving the trigonometric ratios.

Mathematics

1 answer:

polet [3.4K]3 years ago

4 0

Answer:

Defining relations for tangent, cotangent, secant, and cosecant in terms of sine and cosine

Step-by-step explanation:

<h2>HOPE THIS HELPS IM SINGLE 13 STRAIGHT AND IMMA GIRL ;)</h2>

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What are the supplementary angels?

saw5 [17]

Angle RQN and angle RQS, because they will add up to 180 degrees

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2 years ago

Please help me I stink at math ☹️

Greeley [361]

4) Part A draw half of a trapezoid
Part B say that they are four sided shapes with a nintey degree angle
5: answers in this order: line, line segment, ray, point

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3 years ago

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A motorist travels from town A to town B, which are 84km apart. If he has completed 7/8 of his journey, what is the distance he

TEA [102]

The distance that he has traveled exists 73km 500m.

<h3>What is the distance?</h3>

Distance exists described as the amount of space between two items or the condition of existing far apart. The distance of an object can be described as the complete path traveled by an object.

Given: A motorist travels from town A to town B, which exists 84km apart. He has finished 7/8 of his journey.

To estimate the distance that he has traveled

He covered 7/8 out of 84 km

So, 7/8 × 84 = 73.5 km

The distance he has traveled = 73 km 500 m

Therefore, the distance that he has traveled exists 73km 500m.

To learn more about distance refer to:

brainly.com/question/26550516

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5 0

1 year ago

Follow the directions to solve the system of equations by elimination. 8x + 7y=39 4x – 14y = -68

harina [27]

Step-by-step explanation:

Hey there!

Here;

The equations are;

$8x + 7y = 39.......(i)$

$4x - 14y = - 68..........(ii)$

Multiplying equation (i) by 2.

16x + 14y = 78

4x - 14y = -68

20x = 10

$x = \frac{10}{20}$

x = 1/2.

Putting value of 'x' in equation (i).

$8 \times \frac{1}{2} + 7y = 39$

$4 + 7y = 39$

$7y = 3 9 - 4$

$y = \frac{35}{7}$

Therefore the value of y is 5.

Check:

Put value of x and y in equation (i).

8x + 7y = 39

$8 \times \frac{1}{2} + 7 \times 5 = 39$

$4 + 35 = 39$

$39 = 39$

(True).

Therefore, the solution is ; (1/2,5).

Hope it helps...

8 0

3 years ago

Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))

BartSMP [9]

By using De Moivre's theorem:

If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ $\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )$
k= 0, 1 , 2, ..... , (n-1)

For The given complex number ⇒ z = 81(cos(3π/8) + i sin(3π/8))


Part (A) find the modulus for all of the fourth roots

∴ The modulus of the given complex number = l z l = 81

∴ The modulus of the fourth root = $\sqrt[4]{z} = \sqrt[4]{81} = 3$

Part (b) find the angle for each of the four roots

The angle of the given complex number = $\frac{3 \pi}{8}$
There is four roots and the angle between each root = $\frac{2 \pi}{4} = \frac{\pi}{2}$
The angle of the first root = $\frac{ \frac{3 \pi}{8} }{4} = \frac{3 \pi}{32}$
The angle of the second root = $\frac{3\pi}{32} + \frac{\pi}{2} = \frac{19\pi}{32}$
The angle of the third root = $\frac{19\pi}{32} + \frac{\pi}{2} = \frac{35\pi}{32}$
The angle of the fourth root = $\frac{35\pi}{32} + \frac{\pi}{2} = \frac{51\pi}{32}$

Part (C): find all of the fourth roots of this

The first root = $z_{1} = 3 ( cos \ \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})$
The second root = $z_{2} = 3 ( cos \ \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})$

The third root = $z_{3} = 3 ( cos \ \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})$
The fourth root = $z_{4} = 3 ( cos \ \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})$

7 0

3 years ago