Huh this gives out no information to answer
3,000. You take 15,000 and multiply by .4 to get how much she spent on rent (6,000). They you subtract the rent money from her total pay to get her money that she spent on living expenses, clothes and entertainment in total (9,000). Since she spent her money in six parts (3+2+1), you divide 9,000 by 6 to get 1,500 to get each part. Since for entertainment she has two parts you multiply 1,500 by 2 to get 3,000.
1-2. The best estimate for the population mean would be sample mean of 60 gallons. Since we know that the sample mean is the best point of estimate. Since sample size n=16 is less than 25, we use the t distribution. Assume population from normal distribution.
3. Given a=0.1, the t (0.05, df = n – 1 = 15)=1.75
4. xbar ± t*s/vn = 60 ± 1.75*20/4 = ( 51.25, 68.75)
5. Since the interval include 63, it is reasonable.
Answer:

Step-by-step explanation:
we know that
In this problem we have a exponential function of the form

where
x ----> is the number of years since 2009
y ----> is the population of bears
a ----> is the initial value
b ---> is the base
step 1
Find the value of a
For x=0 (year 2009)
y=1,570 bears
substitute


so

step 2
Find the value of b
For x=1 (year 2010)
y=1,884 bears
substitute



The exponential function is equal to

step 3
How many bears will there be in 2018?
2018-2009=9 years
so
For x=9 years
substitute in the equation

