First I am going to assume that these are both right triangles based off of look and because it is much easier. Without it you have to use law of sines or law of cosines...
So to find x you must first find y which can be done simply by using the pythagorean theorem. This theorem is defined as the sum of the squared legs is equal to the sum of the hypotenuse or x^2 + y^2 = z^2
If we substitute in the known values 16^2 + y^2 = 20^2 and solve for y we get that y = sqrt(20^2 - 16^2), this then simplifies to y = 12
Finding x is much more annoying, the easiest way I can immediately see is to find the upper angles by doing sin(16/20) and then 90 - sin(16/20) since the complementary angle is the one you want. I don't have a calculator or a trig table with me right now but I will tell you that x will be equal to 12 ÷ the inverse cosine of the angle (90degrees - sin(16/20)).
I am pretty sure the answer is D though because we know for sure y = 12 and x has to be greater than y because the hypotenuse must be larger than both legs. It could be E but you won't know unless you do the math for x. So it is either D or E but I would be surprised if a Professor made you do all of the work just to say it doesn't work...
Answer:
Step-by-step explanation:
the base of the vase will be where the vase touches the x-axis, that is 10 cm, therefore, the base is 10 cm from the wall
:
b) 25 = x^2 -20x +100, we solve for x to find the closest distance since as we move up the vase the distance to the wall gets closer(assume the y-axis is the wall), then
x^2 -20x +75 = 0 (x-15) * (x-5) = 0
x = 15 and x = 5
we reject x = 15
the shortest distance from the top of the vase to the wall is 5 cm
:
c) this is a left shift of the equation y = (x-10)^2
from b) we know that the left shift is 5 cm
10 - 5 = 5 cm from the wall to the base
:
d) y = (x-10+5)^2
y = (x-5)^2
Answer:
1. No, because each x value can only have one y value (one-to-one relationship).
2. No, because each x value can only have one y value (one-to-one relationship).
3. Yes, because one member of the domain is assigned to one member of the range.
Step-by-step explanation:
We are given with two functions here: h(x) is 5^-x and g(x) is 5^x . we are asked in the problem to determine the value of the expression (g-h)(x). In this case, we just have to employ subtraction to the given functions. That is
(g-h)(x) = 5^x - 5^-x
= 5^x -1/5^x
= (5^2x -1)/5^x
I'm not exactly sure what you're asking but <em />I'll give it a go.
A = x -6
