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Kaylis [27]
3 years ago
9

2(x + 4) + 2x + 3 = 3x + 16what does x eqaul​

Mathematics
2 answers:
Ad libitum [116K]3 years ago
7 0

Answer:

x=5

Step-by-step explanation:

2(x+4)+2x+3=3x+16

One solution was found :

                  x = 5

anastassius [24]3 years ago
6 0

Answer:

2x+8+2x+3=3x+16=

2x+2x-3x=-8-3+16=

4x-3x=-11+16=

x=5

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there are 657 lights on you set. on any given day 6 of them burn out and need to be replaced . if each light cost $45 how much d
Klio2033 [76]

Answer:

1890, total cost of lights per week

Step-by-step explanation:

The lights cost 45 dollars per bulb and 6 go out per day, 45×6=270

270 is the cost to replace the bulbs of one day.

270×7=1890.  1890 is the cost for a whole weeks worth of replacing these bulbs.

6 0
3 years ago
2/5 - (-4/3) = what does it equal because im really confused
ira [324]

Answer:

26/15

Step-by-step explanation:

See attached image.

6 0
3 years ago
Please help thanks!!
marin [14]

Number one because...

2(x-1)>=-12

2x-2>=-12

2x>=-10

X>=-5

7 0
3 years ago
What is the conjugate? See image below! Please help asap
Stolb23 [73]

9514 1404 393

Answer:

  • 2 +3i
  • 8 -i√5
  • 7 +2i
  • 4 +√7

Step-by-step explanation:

The conjugate is found by changing the sign of the square root term.‡ (For this purpose, i = √-1.)

a) the sign of 3i is changed: 2 + 3i

b) the sign of sqrt(-5) is changed: 8 -sqrt(-5) = 8 -i√5

c) the sign of 2i is changed: 7 +2i

d) the sign of sqrt(7) is changed: 4 +√7

_____

‡ Actually, the conjugate of a binomial is formed by changing the sign <em>between</em> terms. The purpose is to allow the product of the binomial and its conjugate to be the difference of squares.

Conventionally, the conjugate of a complex number is the value with the sign of the imaginary part reversed. That is why (-2i+7)* = 7+2i.

4 0
2 years ago
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
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