I saw the image that should have been included in this problem.
It was a rectangular prism. It can also be identified as a right prism because its bases are aligned one directly above the other and its lateral faces are rectangular.
The image has the following measurements:
length = 7 inches
width = 5 inches
height = 4 inches
volume = length * width * height
v = 7 in * 5 in * 4 in
v = 140 in³ Choice B i believe.
Answer:
Paasche's Index= 168.63= 169
Step-by-step explanation:
<em><u>Products</u></em>
<em><u>Base-Period Current Period</u></em>
Quantities Mean Shipping Quantities Mean Shipping
(Year 1) Cost per Unit ($) (Year 5) Cost per Unit ($)
A 1,500 10.50 4000 15.90
B 5,000 16.25 3000 33.00
C 6,500 12.20 8000 18.40
D 2,500 20.00 3000 35.50
Paasche's Index= ∑ pn.qn/∑po.qn* 100
Where pn is the price of the current year and qn is the quantity of the current year and po. is the price of the base year and qo. is the quantity of the base year.
Paasche's Index is the percentage ratio of the aggregate of given period prices weighted by the quantities sold or consumed in the given period to the aggregate of the base period prices weighted by the given period quantities.
Multiplying the current year prices with the current year quantities and the base year price with the current year quantities we get.
Product pn.qn po.qn
A 15.90* 4000 10.50* 4000
= 63600 =42000
B 33.00*3000 16.25 * 3000
= 99000 = 48750
C 18.40* 8000 12.20 *8000
=147200 =97600
D 35.50* 3000 20.00*3000
<u> =</u><u>106500 60,000 </u><u> </u>
<u>∑ 416300 248350 </u>
<u />
Paasche's Index= ∑ pn.qn/∑po.qn= <u> </u>416300/ 248350 *100 = 1.676=1.68= 168.63= 169
<u />
The correct answer would be-11
Answer:
T = 200 months
Step-by-step explanation:
Given the model to be
dp/dt = p(10-1-10-7p) where p(0) = 6000
dp/dt = p(-1-7p)
dp/dt = -p+7p²
But since P(0) = 6000
We plug this value into the equation
P = -6000+7(6000)²
P = -6000+252000000
P = 251994000. .limiting value
Differentiating dp/dt w.r.t p
dp/dt = -1+14p
dp'/dt = 14p-1
Plugging p(0) = 6000 into the above we have that
dp'/dt = 14(6000)-1
P' = 84000
Time population would be equal to 3/2 the limiting value
T = 3/2× 84000 = 126000
T = 25199400/126000
T = 199.99months
T = 200 months.
