The answer to this question is 10 cm
In this question, you asked the height and given the volume of water(2400cm3), aquarium length(20cm), and aquarium width(12cm).
Then you need to divide the volume with the length and width. The equation would be:
Aquarium height= volume / length / width
Aquarium height= 2400 cm3 / 20cm / 12 cm = 10cm.
It'd be clearer if you'd write: "How many tenths are there in 2 3/5?"
2 3/5 13/5
---------- = ---------- = 26
(1`/10) 1/10
There are 26 tenths in 2 3/5.
Answer:

Step-by-step explanation:
Given
Geometry Progression


Required
Calculate the second term
First, we need to write out the formula to calculate the nth term of a GP

For first term: Tn = 500 and n = 1




For fought term: Tn = 32 and n = 4


Substitute 500 for a

Make r^3 the subject


Take cube roots
![\sqrt[3]{r^3} = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Br%5E3%7D%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)
![r = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=r%20%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)

Using: 
and 




<em>Hence, the second term is 200</em>
Answer:
212
Step-by-step explanation:
13 * 17 = 221
221- 9 = 212