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3 years ago

10

Solve the equation:9 + b/6 = 14

2 answers:

Hoochie [10]3 years ago

5 0

B=30. all you have to do is minus 9 from both sides then multiply 6 to each side so all thats left is the variable

Nadusha1986 [10]3 years ago

4 0

Answer is 30
14-9=5
5×6=30

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The two objects are the same height, and the cylinder is just wide enough for the the box to fit inside with all 4 vertical edge

OLEGan [10]

Answer:

The answer is below

Step-by-step explanation:

The volume of a box with a length of l, width of w and a height of h is given by the formula:

volume of the box = length * width * height = lwh

The volume of a cylinder with a height of h, and radius r is given by the formula:

volume of the cylinder = π * radius² * height = πr²h

Since the box and the cylinder have the same height and the cylinder is wide enough for the box to be placed inside, this means that the box has a volume greater than that of the cylinder. Hence:

If the box can take 8 cups, the cylinder would be able to take 10 cups.

7 0

2 years ago

Write the equation of the line through the indicated point with the indicated slope. write the final answer in the form y equals

Assoli18 [71]

y = - 4x + 13

slope = -4

y-intercept = 13

8 0

3 years ago

What is the volume of a cylinder, in cubic cm, with a height of 19cm and a base diameter of 6cm? Round to the nearest tenths pla

SVETLANKA909090 [29]

Answer:

It is about 537.2

Step-by-step explanation:

V= π · r^2 · h

V= π · 3^2 · 19

V≈ 537.2

6 0

3 years ago

John gets paid $6 for each of the first 40 toy cars he makes in a week. For any addition toy cars beyond 40, his pay increases b

jeka57 [31]

48 times 6 and that will be your answer

3 0

3 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago