1. 0 > 3x - 3 - 6
0 > 3x -9
9 > 3x
3 > x
It would be a closed circle starting from 3 going to the right.
2. 4x + 1 - 1 >/ -8
4x >/ -8
x >/ -2
It would be an open circle starting from -2 going to the right.
3. -1 </ 2n + 4 - 5
-1 </ 2n -1
0 </ 2n
Undefined.
4. -6 > 5n + 5 + 4
-6 > 5n + 9
-15 > 5n
-3 > n
It would be a closed circle going to the right
Answer:

Step-by-step explanation:
Using Tangent Secant theorem:
(x)² = (2)(2+6)
x² = 2(8)
x² = 16
Answer:
-1,0,2,-2,0 in that order
Step-by-step explanation:
Answer:
The answer is the option C
cube root of 
Step-by-step explanation:
Remember that
![a^{\frac{x}{y}} =\sqrt[y]{a^{x}}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bx%7D%7By%7D%7D%20%3D%5Csqrt%5By%5D%7Ba%5E%7Bx%7D%7D)
in this problem we have

therefore
![2^{\frac{4}{3}} =\sqrt[3]{2^{4}}=\sqrt[3]{16}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B2%5E%7B4%7D%7D%3D%5Csqrt%5B3%5D%7B16%7D)