Answer:
<h2>x = -11</h2>
Step-by-step explanation:
In algebra, the goal is always to isolate the variable, so that its value can be determined.
<h3>Step 1: Add x</h3>
6 + x = -5
<h3>Step 2: Subtract 6</h3>
x = -11
<h3>Step 3: Check</h3>
6 = -5 - -11
6 = -5 + 11
6 = 6 ✔
<h3>Step 4: Answer</h3>
x = -11
I'm always happy to help :)
Answer:
<em>x - 3y = 6</em>
Step-by-step explanation:
<u>Equation of the line in intercept form</u>
The intercept form of the equation of a line is:
Where:
a = x-intercept
b = y-intercept
The standard form of a line is:
Ax + By = C
The given line has a=6 and b=-2, thus:
Multiplying by 6:
x - 3y = 6
This is the required standard form of the line.
Thus, the standard form of the line is:
x - 3y = 6
Answer:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
Step-by-step explanation:
The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median.
The first quartile(Q1) separates the lower 25% from the upper 75% of a set. So 25% of the values in a data set lie at or below the first quartile, and 75% of the values in a data set lie at or above the first quartile.
The third quartile(Q3) separates the lower 75% from the upper 25% of a set. So 75% of the values in a data set lie at or below the third quartile, and 25% of the values in a data set lie at or the third quartile.
The answer is:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
Answer:
Brent’s club has more possible team combinations because there are more members to choose from
Step-by-step explanation:
Brents club can be created in C12 6 =12!/6!/6!=7*8*9*10*11*12/(2*3*4*5*6)=
=924 variants
Miguel's club can be created in C10 6=10!/6!/4!=7*8*9*10/(2*3*4)=210 variants
924>210 so Brent’s club has more possible team combinations because there are more members to choose from
