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lesya [120]
3 years ago
11

HELLLLLLLLLLLLLLLLLLLLLP

Mathematics
1 answer:
kkurt [141]3 years ago
6 0

So 10/2 simplified is 5/1 which is on point 5. -9/2 is already simplified so in decimal form it is -4.5 which is -4 1/2, so you go down from 0 and mark it right where the BLUE dot is and the GREEN dot is 5/1. Hope this helps! :)

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Math help please help me with this page
White raven [17]
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What does "intersecting" mean?  Look it up if you're not sure.

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5 0
3 years ago
a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.​
Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

A_x=50cos(89.75) so

A_x=.22

B_x=200cos(0) so

B_x=200 and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

C_x=200 (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

A_y=50sin(89.75) so

A_y=50 (which I'm counting as 2 sig fig's)

B_y=200sin(0) so

B_y=0 and we need to add those results together.

C_y=50

Now for the resultant magnitude:

C_{mag}=\sqrt{(200)^2+(50)^2}  and that gives us a final magnitude of

C_{mag}=206 m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

tan^{-1}(\frac{50}{200})=14

The girl is 206 meters from her starting point at an angle of 14 degrees

4 0
3 years ago
Find the side in of point a to point c
vladimir1956 [14]

Step 1:

Calculate the measure of angle ∠ABC

\angle DBC+\angle ABC=180(\text{ sum of angles on a straight line)}\angle ABC=65^0\begin{gathered} \angle DBC+\angle ABC=180 \\ \angle DBC+65^0=180^0 \\ \angle DBC=180^0-65^0 \\ \angle DBC=115^0 \end{gathered}

From the triangle in the question,

a=10\operatorname{km},c=15\operatorname{km},B=115^0

Step 2:

Calculate the value of AB using the cosine rule below

b^2=a^2+c^2-2\times a\times c\times\cos B

By substituting the values, we will have

\begin{gathered} b^2=a^2+c^2-2\times a\times c\times\cos B \\ b^2=10^2+15^2-2\times10\times15\times\cos 115^0 \\ b^2=100+225-300\times(-0.4226) \\ b^2=325+126.78 \\ b^2=451.78 \\ \text{Square root both sides} \\ \sqrt[]{b^2}=\sqrt[]{451.78} \\ b=21.26\operatorname{km} \end{gathered}

Hence,

The distance of point A to point C is = 21.26km

3 0
1 year ago
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velikii [3]

Answer:

x < -3

Step-by-step explanation:

2x - 3 < -9

Add 3 to each side

2x - 3+3 < -9+3

2x < -6

Divide by 2

2x/2 < -6/2

x < -3

5 0
3 years ago
Please help me quickly first person to answer gets branliest
ivolga24 [154]
The answer should be 117.6. tell the teacher that the amount of meters is wrong or the answers are wrong

sorry :(
3 0
3 years ago
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