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OLga [1]
2 years ago
13

There are 4 fruit trees in a yard and each tree produced 15 kilograms of fruit this year. If the fruit is evenly split between 6

families, how many kilograms of fruit does each family get?
Mathematics
2 answers:
-BARSIC- [3]2 years ago
6 0
I believe each family would get 10 kilograms
kogti [31]2 years ago
4 0
Each family will get 10 kilograms.
4 x 15 = 60
60 ÷ 6 = 10
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A study of commuting times reports the travel times to work of a random sample of 20 employed adults in New York State. The mean
Elodia [21]

Answer:

The standard error of the mean = 5.14 mins

Step-by-step explanation:

Number of random sample (n) = 20

Mean(X) = 31.25 mins

Standard deviation (α) = 23.7 mins

Standard error of mean =

standard deviation / √sample size

= 23.7/√20

= 23.7/4.4721

= 5.14 mins

5 0
3 years ago
It’s the same distance from the second base to the first base from the second base to third-base the angle formed by the first b
Margaret [11]

Answer:

Distance of home plate to 1st base is equal to home plate to 3rd base

Step-by-step explanation:

Let's first assign each position:

A: home base

B: 1st base

C: 2nd base

D: 3rd base

The information given:

'It’s the same distance from the second base to the first base from the second base to third-base' tells us BC = CD

'the angle formed by the first base second base and Homeplate has the same measure as the angle formed by the base second base home plate' tells us angle(BCA) = angle(DCA)

Check for congruency between triangle ABC and ADC

BC = CD - side congruency (S)

angle(BCA) = angle(DCA) - angle congruency (A)

CA = CA - side congruency (S)

So triangle ABC and ADC fullfill the criteria of congruence property as SAS.

Since both triangle are congruent, another side of the triangles AB and AD must be the same too.

AB = home plate to 1st base

AD = home plate to 3rd base

Therefore we can conclude that the distance of home plate to 1st base is equal to home plate to 3rd base

3 0
3 years ago
Research studies show that the relationship between the tire pressure of a vehicle’s tires and the life of the tires is quadrati
vlabodo [156]

Answer:

-2.40947

Step-by-step explanation:

4 0
2 years ago
Round 6.5472 to<br> the hundredths place.
Ugo [173]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If f(x)=x^3-x+2, then (f^-1)'(2)
yawa3891 [41]

Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,

f\left(f^{-1}(x)\right) = x

\implies f^{-1}(x)^3 - f^{-1}(x) + 2 = x

which is a cubic polynomial in f^{-1}(x) with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).

Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.

f'(x) = 3x² - 1 = 0   ⇒   x = ±1/√3

So, we have three subsets over which f(x) can be considered invertible.

• (-∞, -1/√3)

• (-1/√3, 1/√3)

• (1/√3, ∞)

By the inverse function theorem,

\left(f^{-1}\right)'(b) = \dfrac1{f'(a)}

where f(a) = b.

Solve f(x) = 2 for x :

x³ - x + 2 = 2

x³ - x = 0

x (x² - 1) = 0

x (x - 1) (x + 1) = 0

x = 0   or   x = 1   or   x = -1

Then \left(f^{-1}\right)'(2) can be one of

• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);

• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or

• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)

6 0
2 years ago
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