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Sergio039 [100]
3 years ago
11

( sorry the picture isn’t that good ) Find the area of the unfolded box bottom. Show your work. ( 30 in. on top 5 in. in the cor

ners 20 in. on the sides )

Mathematics
1 answer:
taurus [48]3 years ago
8 0

Answer:

1100 in²

Step-by-step explanation:

Find the area of the boxes separately and add them

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Lunna [17]

Answer:hbygyhbhbhb

scamed for points

Step-by-step explanation:

5 0
3 years ago
Find g(4) and f(g(4)) <br> f(x)=x^2-x+1 <br> g(x)= 3x-5
Ira Lisetskai [31]

Answer:

g(4)  = 7 and f(g(4)) = 43

Step-by-step explanation:

First find g:

g(x) = 3x-5

g(x) = 3(4) - 5

g(x) = 12 - 5

g(x) = 7

Plug in:

f(g(4))

f(7)

Now, find f:

7^2 - 7 + 1

49 - 7 + 1

42 + 1

f(x) = 43

5 0
2 years ago
The question is show a dilation of a rectangle with a dilation of 8/3
miv72 [106K]

It's always easier to understand a concept by looking at specific examples with pictures, so I suggest looking at the dilation examples below first...before you try to internalize the steps listed below and that explain the general formula for dilating a point with coordinates of (2,4) by a scale factor of <span><span>12</span><span>12</span></span>.

<span><span>1) multiply both coordinates by scale factor<span>(<span><span>2⋅<span>12</span>,4⋅<span>12</span></span><span>2⋅<span>12</span>,4⋅<span>12</span></span></span>)</span></span><span>2)

2. Simplify(1,2)</span><span>3)

3. Graph(if required)<span> </span></span></span>
5 0
3 years ago
Solve 2(1 – x) &gt; 2x<br> this is my question for algebra
Rudik [331]

To solve this, you need to isolate/get the variable "x" by itself in the inequality:

2(1 - x) > 2x     Divide 2 on both sides

\frac{2(1-x)}{2} >\frac{2x}{2}

1 - x > x     Add x on both sides to get "x" on one side of the inequality

1 - x + x > x + x

1 > 2x        Divide 2 on both sides to get "x" by itself

\frac{1}{2} >x  or  x     (x is any number less than 1/2)

[Another way you could've solved it]

2(1 - x) > 2x     Distribute 2 into (1 - x)

(2)1 + (2)(-x) > 2x

2 - 2x > 2x      Add 2x on both sides

2 - 2x + 2x > 2x + 2x

2 > 4x    Divide 4 on both sides to get "x" by itself

\frac{2}{4} >\frac{4x}{4}

\frac{1}{2} >x

6 0
2 years ago
The sum ∫2−2() ∫52()−∫−1−2() can be written as a single integral in the form ∫() determine and
kow [346]

We have

\displaystyle \int_{-2}^2 f(x) \, dx - \int_{-2}^{-1} f(x) \, dx = \int_{-1}^2 f(x) \, dx

so that

\displaystyle \int_{-2}^2 f(x) \, dx + \int_2^5 f(x) \, dx - \int_{-2}^{-1} f(x) \, dx \\\\ ~~~~~~~~~~~~ =  \int_{-1}^2 f(x) \, dx + \int_2^5 f(x) \, dx \\\\ ~~~~~~~~~~~~ = \boxed{\int_{-1}^5 f(x) \, dx}

6 0
1 year ago
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