Your photo is super blurry! I can’t read parts of the problems, so I can’t exactly help you. Sorry! Good luck.
Answer:
The answer is

Step-by-step explanation:
The midpoint M of two endpoints of a line segment can be found by using the formula

where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
Q(2,4) and R(-3,9)
The midpoint is

We have the final answer as

Hope this helps you
The triangle to solve for has a leg or 12 feet, hypotenuse of 20 feet, so solve for Pythagoras

for a

a = 16 feet
Answer: 
Step-by-step explanation:
By definition, an Isosceles triangle has two equal sides and its opposite angles are congruent.
Observe the figure attached, where the isosceles triangle is divided into two equal right triangles.
So, in this case you need to use the following Trigonometric Identity:

In this case, you can identify that:

Substituting values, and solving for "x", you get:

Therefore, the length of BC rounded to nearest tenth, is:

Answer:
Step-by-step explanation:
Putting value of x = 2 in the equation
F(2) = 2(2) - 6
= 4 - 6
= - 2