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Darina [25.2K]
3 years ago
13

Find the value of x, y, and z.

Mathematics
1 answer:
horsena [70]3 years ago
7 0
X= 45
z=45
y=90
180-135 is 45 degrees for Z. X is also 45 while y then becomes 90. as 90+45+45=180.
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An animal shelter takes in an average of 5 animals per day. The shelter must keep its total occupancy below 300. Currently, the
Akimi4 [234]

Answer:

B. x<27

Step-by-step explanation:

300-165=135

135/5=27

8 0
3 years ago
-4i+ 3i= i- 8+ 3i- 12
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

-4i+3i=i-8+3i-12

-i=4i-20

20=4i+i

20=5i

20/5=i

4=i

4 0
3 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
Use the photo to answer
mr_godi [17]
The circumference is 113.04 and multiple that by 7.50 to get 847.8 and i believe that’s the answer.
3 0
3 years ago
How to write 224466 with a coma
stira [4]
224,466

hope it helps
3 0
3 years ago
Read 2 more answers
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