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makvit [3.9K]
3 years ago
10

15. A rectangle has a base of 8 inches and a height of 2 inches. What is the length of one diagonal?

Mathematics
1 answer:
Leokris [45]3 years ago
8 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>

<em>G</em><em>ood</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>

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  • At 1pm, the number of bacteria in the dish is 1,000,000
  • At 12pm, the number of bacteria in the dish is 500,000

Step-by-step explanation:

Given the information on the table

\left|\begin{array}{c|c}$Hour&$Number of Bacteria (in millions)\\---&--------------\\12 p.m.&\\1 p.m.&\\12 p.m.&\\2 p.m.&\\3 p.m.&\\4 p.m.&\\5 p.m.&32\\6 p.m.&64\end{array}\right|

We are to follow the pattern to determine how many million bacteria were in the dish at  1 p.m. and 12 p.m.

Now:

32=2^5\\64=2^6

It therefore means that the bacteria population doubles every hour. Following this pattern and reducing the exponents by 1 backwards, we have:

\left|\begin{array}{c|c}$Hour&$Number of Bacteria (in millions)\\---&--------------\\12 p.m.&2^{-1}=0.5\\1 p.m.&2^0=1\\12 p.m.&2^1=2\\2 p.m.&2^2=4\\3 p.m.&2^3=8\\4 p.m.&2^4=16\\5 p.m.&2^5=32\\6 p.m.&2^6=64\end{array}\right|

Therefore:

  • At 1pm, the number of bacteria in the dish is 1,000,000
  • At 12pm, the number of bacteria is 0.5 million=0.5 X 1,000,000=500,000
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