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diamong [38]
3 years ago
11

Janae has a soap bottle that has $474$ mL of liquid soap. Each push of the pump uses $8$ mL of soap. There needs to be at least

$50$ mL of soap in the bottle for the pump to work.
Mathematics
1 answer:
bixtya [17]3 years ago
6 0

Answer:

53 pushes

Step-by-step explanation:

Total Volume of soap = 474 mL

Volume per push = 8mL

Mimimum volume required = 50mL

The equation which represents the number of push, x that can be made :

Total volume = minimum volume + (volume per push * number of pushes)

Total volume = 50 + (8 * x)

474 ≤ 50 + 8x

474 - 50 ≤ 8x

424 ≤ 8x

53 ≤ x

The number of pushes that can be made = 53

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3 years ago
Read 2 more answers
If you flip a fair coin 7 times, what is the probability that you will get exactly 4 tails?
andre [41]

Probability that you will get exactly 4 tails, if you flip a fair coin 7 times is: \frac{35}{128}

Step-by-step explanation:

We need to find the probability that you will get exactly 4 tails, if you flip a fair coin 7 times.

This is the combination question.

The total combinations will be: 2^7=128

Now, finding number of ways we can get exactly 4 tiles:

We will use the formula:

^nC_k=\frac{n!}{k!(n-k)!}

in our given question, n= 7, k= 4

Putting values:

^nC_k=\frac{n!}{k!(n-k)!}\\^7C_4=\frac{7!}{4!*3!}\\ ^7C_4=\frac{7*6*5*4!}{4!*3!}\\ ^7C_4=\frac{7*6*5}{6}\\ ^7C_4=35

So, Probability that you will get exactly 4 tails, if you flip a fair coin 7 times is: \frac{35}{128}

Keywords: Probability

Learn more about Probability at:

  • brainly.com/question/1637111
  • brainly.com/question/2254182
  • brainly.com/question/2264295

#learnwithBrainly

7 0
3 years ago
Calculate the discriminant to determine the number solutions. y = x ^2 + 3x - 10
Nataly_w [17]

1. The first step is to find the discriminant itself. Now, the discriminant of a quadratic equation in the form y = ax^2 + bx + c is given by:

Δ = b^2 - 4ac

Our equation is y = x^2 + 3x - 10. Thus, if we compare this with the general quadratic equation I outlined in the first line, we would find that a = 1, b = 3 and c = -10. It is easy to see this if we put the two equations right on top of one another:

y = ax^2 + bx + c

y = (1)x^2 + 3x - 10

Now that we know that a = 1, b = 3 and c = -10, we can substitute this into the formula for the discriminant we defined before:

Δ = b^2 - 4ac

Δ = (3)^2 - 4(1)(-10) (Substitute a = 1, b = 3 and c = -10)

Δ = 9 + 40 (-4*(-10) = 40)

Δ = 49 (Evaluate 9 + 40 = 49)

Thus, the discriminant is 49.

2. The question itself asks for the number and nature of the solutions so I will break down each of these in relation to the discriminant below, starting with how to figure out the number of solutions:

• There are no solutions if the discriminant is less than 0 (ie. it is negative).

If you are aware of the quadratic formula (x = (-b ± √(b^2 - 4ac) ) / 2a), then this will make sense since we are unable to evaluate √(b^2 - 4ac) if the discriminant is negative (since we cannot take the square root of a negative number) - this would mean that the quadratic equation has no solutions.

• There is one solution if the discriminant equals 0.

If you are again aware of the quadratic formula then this also makes sense since if √(b^2 - 4ac) = 0, then x = -b ± 0 / 2a = -b / 2a, which would result in only one solution for x.

• There are two solutions if the discriminant is more than 0 (ie. it is positive).

Again, you may apply this to the quadratic formula where if b^2 - 4ac is positive, there will be two distinct solutions for x:

-b + √(b^2 - 4ac) / 2a

-b - √(b^2 - 4ac) / 2a

Our discriminant is equal to 49; since this is more than 0, we know that we will have two solutions.

Now, given that a, b and c in y = ax^2 + bx + c are rational numbers, let us look at how to figure out the number and nature of the solutions:

• There are two rational solutions if the discriminant is more than 0 and is a perfect square (a perfect square is given by an integer squared, eg. 4, 9, 16, 25 are perfect squares given by 2^2, 3^2, 4^2, 5^2).

• There are two irrational solutions if the discriminant is more than 0 but is not a perfect square.

49 = 7^2, and is therefor a perfect square. Thus, the quadratic equation has two rational solutions (third answer).

~ To recap:

1. Finding the number of solutions.

If:

• Δ < 0: no solutions

• Δ = 0: one solution

• Δ > 0 = two solutions

2. Finding the number and nature of solutions.

Given that a, b and c are rational numbers for y = ax^2 + bx + c, then if:

• Δ < 0: no solutions

• Δ = 0: one rational solution

• Δ > 0 and is a perfect square: two rational solutions

• Δ > 0 and is not a perfect square: two irrational solutions

6 0
3 years ago
Write the equation, in standard form, of a polynomial of the least degree with integral
Hitman42 [59]

Answer:

f

(

x

)

=

3

x

3

−

5

x

2

−

47

x

−

15

Explanation:

If the zero is c, the factor is (x-c).

So for zeros of

−

3

,

−

1

3

,

5

, the factors are

(

x

+

3

)

(

x

+

1

3

)

(

x

−

5

)

Let's take a look at the factor

(

x

+

1

3

)

. Using the factor in this form will not result in integer coefficients because

1

3

is not an integer.

Move the

3

in front of the x and leave the

1

in place:

(

3

x

+

1

)

.

When set equal to zero and solved, both

(

x

+

1

3

)

=

0

and

(

3

x

+

1

)

=

0

result in

x

=

−

1

3

.

f

(

x

)

=

(

x

+

3

)

(

3

x

+

1

)

(

x

−

5

)

Multiply the first two factors.

f

(

x

)

=

(

3

x

2

+

10

x

+

3

)

(

x

−

5

)

Multiply/distribute again.

f

(

x

)

=

3

x

3

+

10

x

2

+

3

x

−

15

x

2

−

50

x

−

15

Combine like terms.

f

(

x

)

=

3

x

3

−

5

x

2

−

47

x

−

15

5 0
3 years ago
How do you solve this equation thankyou. <br> 5n+34=-2(1-7n)
JulijaS [17]
5n+34=-2(1-7n) \\&#10;5n+34=-2+14n\\&#10;-9n=-36\\&#10;n=4
5 0
3 years ago
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