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diamong [38]
3 years ago
11

Janae has a soap bottle that has $474$ mL of liquid soap. Each push of the pump uses $8$ mL of soap. There needs to be at least

$50$ mL of soap in the bottle for the pump to work.
Mathematics
1 answer:
bixtya [17]3 years ago
6 0

Answer:

53 pushes

Step-by-step explanation:

Total Volume of soap = 474 mL

Volume per push = 8mL

Mimimum volume required = 50mL

The equation which represents the number of push, x that can be made :

Total volume = minimum volume + (volume per push * number of pushes)

Total volume = 50 + (8 * x)

474 ≤ 50 + 8x

474 - 50 ≤ 8x

424 ≤ 8x

53 ≤ x

The number of pushes that can be made = 53

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F(x) = 8 – 3x<br>Evaluate f(9)​
Readme [11.4K]
F(x) = 8 - 3x

f(9) = 8 - 3(9)
= 8 - 27
= -19

hope this helps!
5 0
3 years ago
In a certain year, the price of gasoline rose by 20% during January, fell by 20% during February, rose by 25% in March, and fell
satela [25.4K]

Using decimal multipliers, it is found that the value of x is of 16.67.

<h3>What is a decimal multiplier?</h3>

Increases of a% or decreases of a% re represented by decimal values, as follows:

  • The equivalent multiplier for an increase of a% is given by: \frac{100 + a}{100}
  • The equivalent multiplier for an decrease of a% is given by: \frac{100 - a}{100}

In this problem:

  • The price at the beginning of January was of a.
  • Increase of 20% in January, hence 1.2a.
  • Decrease of 20% in February, hence 1.2(0.8)a.
  • Increase of 25% in March, hence 1.2(0.8)(1.25)a.
  • Decrease of x% in April, hence 1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

The price of gasoline at the end of April was the same as it had been at the beginning of January, hence:

a =1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

1.2\left(\frac{100 - x}{100}\right) = 1

\left(\frac{100 - x}{100}\right) = \frac{1}{1.2}

\frac{100 - x}{100} = 0.8333

100 - x = 83.33

x = 16.67

The value of x is of 16.67.

To learn more about decimal multipliers, you can take a look at brainly.com/question/24952336

6 0
2 years ago
Martha estimated there were 83 marbles in a jar for a contest. The actual number of marbles in the jar was 105. What was the per
Luba_88 [7]

Answer:

26.5%

Step-by-step explanation:

i did the math, that answer should be correct, but the question is stated  strange.

4 0
2 years ago
Find x<br><br><br>A) 12<br><br>B) 13 <br><br>C) 11<br><br>D) 10
Soloha48 [4]

We know that the sum of arc ND and arc ML divided by 2 is equivalent to 6x + 23.

Thus, we can form an equation:

6x + 23 = (11x + 8 + 3x + 14)/2

Simplify:

6x + 23 = (14x + 22)/2

Simply again:

6x + 23 = 7x + 11

Subtract 6x from both sides:

23 = x + 11

Subtract 11 from both sides

x = 12

Option A, or x = 12

-T.B.

5 0
3 years ago
Please help me with this question step by step. A rectangle has a width of 2x exponent 2 +4x+1) and a length of (8-x). What is t
timurjin [86]

Answer:

A = (2x² + 4x + 1) (8 − x)

A = -2x³ + 12x² + 31x + 8

Step-by-step explanation:

W = 2x² + 4x + 1

L = 8 − x

Area is width times length.

A = (2x² + 4x + 1) (8 − x)

If you wish, you can simplify with distribution.

A = 8 (2x² + 4x + 1) − x (2x² + 4x + 1)

A = 16x² + 32x + 8 − 2x³ − 4x² − x

A = -2x³ + 12x² + 31x + 8

6 0
3 years ago
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