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2 years ago

The quotient of 20 and a number will be 10

Mathematics

1 answer:

sattari [20]2 years ago

4 0

Answer:

200

Step-by-step explanation:

200 divided by 10 equals 20. Hope this helps!!!! Good luck on the assignment!!!

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What is the solution to the equation P over 9= 72?

Fed [463]

P / 9 = 72

Multiply both sidess by 9

P / 9 (9) = 72 (9)

p = 648

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3 years ago

What is the solution to the following system of linear equations?

Lostsunrise [7]

x − 2y = −1 => x = 2y -1

2x + y = −12
2(2y - 1) + y = -12
4y - 2 + y = -12
5y = -10
y = -2
x = 2·(-2) - 1
x = -4 - 1
x = -5

Answer D (-5,-2)

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3 years ago

There are 3 students to 1 adult on a field trip.You need to find the number of adults needed for 24 students. What would the sec

AysviL [449]

Answer: 24 : 8 or 24 to 8

Step-by-step explanation:

Let the number of adults be x

3/1 = 24/x . We have to do cross multiplication,

24 = 3x

x = 8

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3 years ago

Choose the midpoint of the line segment with endpoints at (5, 9) and (11, 15).

Tcecarenko [31]

Answer:

C) (8,12)

Step-by-step explanation:

$MP= (\frac{x_1+x_2}{2} )(\frac{y_1+y_2}{2} )\\MP= (\frac{5+11}{2} )(\frac{9+15}{2} )\\MP= (\frac{16}{2} )(\frac{24}{2} )\\MP= (8,12)$

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3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

The quotient of 20 and a number will be 10​

The quotient of 20 and a number will be 10