Ask question

Ask question

All categories

3 years ago

5

What is 5.06 times 2.10. Pease show work

1 answer:

Alecsey [184]3 years ago

3 0

$your \: answer \: is \: 10.626$

$im \: sorry \: i \: cant \: show \: work \: i \: used \: a \: calculator$

You might be interested in

Factor completely. If a polynomial is prime, state this<br> -9+18x²+21x

grin007 [14]

Factoring completely you get: 3(3x-1)(2x+3)

3 0

3 years ago

Find the inverse of f(x)=4x+3

zhuklara [117]

$f(x) = 4x+3\\\\\text{Write f(x) as y = 4x+3}\\\\\text{Replace x with y,}\\\\x =4y +3\\\\\text{Solve for y:}\\\\ \implies x =4y+3\\\\\implies 4y = x-3 \\\\\implies y =\dfrac{x-3}4\\\\\implies f^{-1} (x) = \dfrac{x-3}4\\\\\text{This is the inverse of f(x)}$

4 0

2 years ago

Help me for a Through f

Sati [7]

I think the answer is 37.7

8 0

3 years ago

What does the E stand for in 3.1536e+17

V125BC [204]

Answer:

well e stands for like what you multiply

Step-by-step explanation:

like well here is an example y=16e and you have to find what e stands for so E=

3 0

2 years ago

Read 2 more answers

A circle is shown. 2 raddi are drawn. A chord connects the points of the radii on the circle to each other to form a triangle. T

iragen [17]

Answer:

$(5\pi-11.6)ft^2$

Step-by-step explanation:

Given:

Length of radius of circle = 5 feets

Length of perpendicular bisector = 4 feets

To find:

Area of the shaded portion of the circle

Solution:

As OD is perpendicular bisector of AB,

$AB=2AD=2(2.9)=5.8\,\,feets$

$\angle ODA=90^{\circ}$

Area of $\Delta AOB$ = 1/2 (base) × (height) = $\frac{1}{2}\times 4\times 5.8=11.6$ square feets

Area of sector AOBC = $\frac{\angle AOB}{360^{\circ}}\pi(r^2)=\frac{72^{\circ}}{360^{\circ}}\pi(5^2)=5\pi$ square feets

Here, r denotes radius of circle

So,

Area of shaded portion = Area of sector AOBC - Area of $\Delta AOB$ = $(5\pi-11.6)ft^2$

3 0

3 years ago