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Sever21 [200]
4 years ago
14

An object is attached to a hanging unstretched ideal and massless spring and slowly lowered to its equilibrium position, a dista

nce of 6.4 cm below the starting point. If instead of having been lowered slowly the object was dropped from rest, how far then would it then stretch the spring at maximum elongation?
Physics
1 answer:
Llana [10]4 years ago
6 0

Answer:

        h = 12.8 cm

Explanation:

from the equation we are given the following:

distance = 6.4 cm

  • when the object is being lowered the weight is equal to the spring force

        weight = spring force

         mg = ky ... equation 1

  • potential energy to stretch a spring = work done by the spring

        mgh = 0.5 x k x h^{2} ....equation 2

  • substituting equation 1 into equation 2

                kyh =  0.5 x k x h^{2}

                y =  0.5 x h

                2y = h

  • where y = 6.4 , the maximum elonf=gation becomes

          h = 2 x 6.4 = 12.8 cm

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Answer :

New force becomes, F' = 1.83 N

Explanation:

Let two point charges exert a force of 7.35 N force on each other. The electric force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}

q_1\ and\ q_2 are charges

r is the distance between charges if the distance between them is increased by a factor of 2, r' = 2r

New force is given by :

F'=\dfrac{kq^2}{r'^2}

F'=\dfrac{kq^2}{(2r)^2}

F'=\dfrac{1}{4}\dfrac{kq^2}{r^2}

F'=\dfrac{1}{4}\times 7.35

F' = 1.83 N

So, the new force between charges will be 1.83 N. Therefore, this is the required solution.          

3 0
3 years ago
A car travels in the + x-direction on a straight and level road. For the first 4.00 s of its motion, the average velocity of the
sergejj [24]

Answer:

25 m

Explanation:

The relationship between Velocity, distance and time is given as

S = v/t........................... Equation 1

Where S = average velocity of the car, d = distance covered by the car, t = time

Making d the subject of the equation,

d = vt.................... Equation 2

Given: v = 6.25 m/s, t = 4.00 s.

Substitute into equation 2,

d = 6.25(4)

d = 25 m.

Hence, the distance traveled by the car = 25 m

8 0
4 years ago
Which of the following is an element?
Sergeeva-Olga [200]
Oxygen is on the Periodic Table of Elements as a member of the chalcogen group. It is a chemical element represented by the symbol O.

B would've also been a right answer if it weren't for the Dioxide part.

But the answer is C. Oxygen.
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3 years ago
Carbon nanotubes are made of the same material as the graphite found in pencils, a material soft enough to leave an image on
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Explanation:

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3 years ago
A 325 g object attached to a horizontal spring moves in simple harmonic motion with a period of 0.220 s. The total mechanical en
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Answer:

Explanation:

Total mechanical energy = 1/2 m ω²A² where ω is angular frequency and A is amplitude .

Given

1/2 m ω²A² = 5.46

ω²A² = 2 x 5.6 / m

= 2 x 5.6 / .325

= 34.46

ωA = 5.87

maximum speed = ωA = 5.87 m /s

B )

angular frequency = 2π / T , T is period of oscillation .

= 2 x 3.14 / .22

= 28.54 s⁻¹

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C)

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28.54 X A = 5.87

A = .2056 m

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3 years ago
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