Question

A projectile is launched from ground level at an angle of 50.0 degrees above the horizontal with a speed of 30.0 m/s. If the projectile is moving over level ground, how long is it in the air before it again contacts the ground

Answer 1

Answer:

4.69 s

Explanation:

u = Initial velocity = 30 m/s

$\theta$ = Angle of launch = $50^{\circ}$

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Time taken by the projectile to land is given by

$t=\dfrac{2u\sin\theta}{g}\\\Rightarrow t=\dfrac{2\times 30\times \sin50^{\circ}}{9.81}\\\Rightarrow t=4.69\ \text{s}$

The time the projectile is in the air before it contacts the ground again is 4.69 s.