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statuscvo [17]
3 years ago
15

CosA+cosB+cosC+cos(A+B+C)= cos(A+B).cos(B+C).cos(C+A)

Mathematics
1 answer:
RoseWind [281]3 years ago
8 0

Answer:

cos (A+B+C)

Step-by-step explanation:

as A,B,C, are triangle we have A,B and C as 180

cost

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If the side length of a square pyramid is triple and the slant height is divided by 5 what would be the formula to find the modi
valentina_108 [34]
If the original side length is "s" and the original slant height is "h", the original surface area is
.. S = (base area) +(lateral area)
.. S = s² +(1/2)*(4s)*h
.. S = s(s +2h)

Now, if we make these replacements: s ⇒ 3s, h ⇒ h/5, we have
.. S' = (3s)(3s +2h/5)
.. S' = 9s² +(6/5)s*h . . . . . . . the formula for the modified area (in terms of original dimensions)

_____
Of course, in terms of the modified dimensions, the formula is the same:
.. S' = s'(s' +2h')
5 0
3 years ago
You usually buy a 16.5-ounce bottle of shampoo. There is a new bottle that says it gives you 30% more free.
Katarina [22]

Answer:

\frac{x-16.5}{16.5}=0.30

Hopefully, this is your desired setup. (I noticed the formula you have to fill in there.)

Have a good day.

Step-by-step explanation:

Hi.

You could use the percent change formula.

Since we know it is a percent increase then we will do new-old instead of old-new:

\frac{\text{new}-\text{old}}{\old}

x is the new amount of shampoo.

16.5 is the original amount (old) of shampoo.

The percent increase is 30%=0.30 .

So we have the following equation:

\frac{x-16.5}{16.5}=0.30

We could have found the equation like this:

16.5+16.5(0.30)=x

Subtract 16.5 on both sides:

16.5(0.30)=x-16.5

Divide both sides by 16.5:

0.30=\frac{x-16.5}{16.5}

By us of symmetric property of equality:

\frac{x-16.5}{16.5}=0.30

5 0
3 years ago
Read 2 more answers
Write an equation that represents the line.<br> Use exact numbers.<br> (-2,-1)<br> (4,6)
vazorg [7]

Check the picture below.

to get the equation of any straight line, we simply need two points off of it, so let's use those in the picture

(\stackrel{x_1}{-2}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{6})~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{(-2)}}} \implies \cfrac{6 -1}{4 +2} \implies \cfrac{ 5 }{ 6 }

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{5}{6}}(x-\stackrel{x_1}{(-2)})\implies y-1=\cfrac{5}{6}(x+2) \\\\\\ y-1=\cfrac{5}{6}x+\cfrac{5}{3}\implies y=\cfrac{5}{6}x+\cfrac{5}{3}+1\implies y=\cfrac{5}{6}x+\cfrac{8}{3}

6 0
2 years ago
How much fencing will John need? Use 22/7 for x.
Serjik [45]

Well 22/7 is 3.14 and so on but since there is a little more than 3 you need to make sure he covers up all the fencing places... SO John will need 4 fences

4 0
3 years ago
The sum of 2 numbers is 20 and their product is 90. What are the two numbers? (Note: Write the smaller number first.)
DIA [1.3K]

The two numbers are 8 and 12.

When added, you get a sum of 20.

When multiplied, you get a product of 96.

4 0
3 years ago
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