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alexandr402 [8]
2 years ago
12

Solve for x. In the equation 9x +1/3= x-13

Mathematics
2 answers:
Xelga [282]2 years ago
6 0

Answer:

Step-by-step explanation:

9x+\frac{1}{3}=x-13

9x*3+1/3=x-13

27x+1/3=x-13

27x+1=3(x-13)

27x+1=3x-39

27x-3x=-39-1

24x=-40

x=-5/3

x=-5/3

kirill115 [55]2 years ago
5 0

Answer:

x = - \frac{5}{3}

Step-by-step explanation:

Given

9x + \frac{1}{3} = x - 13 ( multiply through by 3 to clear the fraction )

27x + 1 = 3x - 39 ( subtract 3x from both sides )

24x + 1 = - 39 ( subtract 1 from both sides )

24x = - 40 ( divide both sides by 24 )

x = \frac{-40}{24} = - \frac{5}{3}

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Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2
evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}

Step # 1 : Swap the first and second matrix rows,

\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}

Step # 2 : Cancel leading coefficient in row 2 through R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1,

\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0
3 years ago
Please help! what is the polar equation r = -5 theta in parametric form?<br><br> thank you!
Rudiy27

Use these equations when converting polar equations to parametric equations:

x=r\cos\theta

y=r\sin\theta

We know that r=5\theta, so substitute that into both equations for x and y.

x=5\theta\cos\theta

y=5\theta\sin\theta

Now, replace \theta with any variable that you want to represent the parametric equations in. I'll use the standard variable, t

x=5t\cos t

y=5t\sin t

Thus, r=5\theta represented in parametric form is:

(x,y)=(5t\cos t, 5t \sin t)

Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
246000 in scientific notation
atroni [7]

Answer:

2.46 x 10⁵

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Hey can you please help me posted picture of question
ICE Princess25 [194]
The answer is true.

Method 1:
The given function is a cubic function. And inverse of a cubic function is also a function.

Method 2:
Since the function is one-to-one function i.e it passes the horizontal line test, its function will pass the vertical line test which is a test if a relation is a function or not.

So, yes the inverse of G(x) will be a function.
6 0
3 years ago
Jamal states that ax + b = a(x + c), given a, b, and c are not equal to 0. What must be the value of c for Jamal's statement to
Anna35 [415]

ANSWER

For Jamal statement to be true,

c = \frac{b}{a}

EXPLANATION

The given statement is:

ax + b = a(x + c)

We expand the left hand side to obtain,

ax + b = ax + ac

Subtract ax from from both sides of the equation.

b=ac

We know that, a≠0 , so we can divide through by 'a'.

\frac{b}{a}  = c

6 0
3 years ago
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