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barxatty [35]
3 years ago
14

I need help showing my work plz

Mathematics
1 answer:
madam [21]3 years ago
5 0
It’s already kind of sketched out
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A line is represented by the equation 2x + 3y = 15. What is another way to represent the same line, for solving Y ? Help is need
Lady bird [3.3K]

The another way to represent the same line, for solving y will be:  y= 5-\frac{2}{3}x

<u><em>Explanation</em></u>

Given equation of the line is:  2x+3y=15

"Solving y" means <u>we need to get</u> y <u>alone in left side.</u> So, we will eliminate all other terms except y from the left side.

First we will <u>subtract 2x </u>from both sides. So, we will get......

2x+3y-2x=15-2x\\ \\ 3y=15-2x

Now, we will <u>divide both sides by 3</u> for getting y alone. So.....

\frac{3y}{3}= \frac{15-2x}{3}\\ \\ y= 5-\frac{2}{3}x

Thus, the another way to represent the same line, for solving y will be:  y= 5-\frac{2}{3}x

7 0
4 years ago
How do i turn this to decimals?<br><br> 818/1320<br><br> 1742/2540<br><br> 396/1220
trapecia [35]
You simply divide numerator by denominator
818/1320 = 0.619
1742/2540 = 0.685
396/1220 = 0.32
hope this helps ;3
6 0
4 years ago
Read 2 more answers
Which of the following cannot be the description of a function
suter [353]
No repetition of x values
6 0
3 years ago
Record: 0/2 Score: 0 Penalty: 1 off
SVETLANKA909090 [29]

Newton's Law of Gravitation:

Statement: According to this law, when two mass bodies are separated at finite distance then there must be an attractive force experience by them which is directly proportional to the product of their masses and inversely proportional to the square of their separation.

Consider two mass bodies m1 & m2 be kept at distance d. Then the force of attraction F is given as

                            Fam_{1}.m_{2}

                                 Fa1/d^2

Now, from above equations, we have

                          Fa\frac{m_{1}m_{2}}{d^2}

or,                           F=G\frac{m_{1}m_{2}}{d^2}

Here         G=6.67*10^{-11}Mm^2kg^{-2}   is the universal gravitational constant.

6 0
3 years ago
Please I need help ASAP
andrezito [222]

I think the answer is 0.62

8 0
3 years ago
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