Identify and calculate formulas and examples...
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The expected values of the binomial distribution are given as follows:
1. 214.
2. 21.
3. 31.
<h3>What is the binomial probability distribution?</h3>
It is the <u>probability of exactly x successes on n repeated trials, with p probability</u> of a success on each trial.
The expected value of the binomial distribution is:
E(X) = np
For item 1, the parameters are:
p = 3/7, n = 500.
Hence the expected value is:
E(X) = np = 500 x 3/7 = 1500/7 = 214.
For item 2, the parameters are:
p = 0.083, n = 250.
Hence the expected value is:
E(X) = np = 250 x 0.083 = 21.
For item 3, the parameters are:
p = 1/13, n = 400.
Hence the expected value is:
E(X) = np = 400 x 1/13 = 31.
More can be learned about the binomial distribution at brainly.com/question/24863377
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The true statement will be A.
It is.........................................................
Answer:
480 milligrams.
Step-by-step explanation:
Divide 320 by 92, you get 3.47826087, multiply that by 138 to get your answer (480).
