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worty [1.4K]
3 years ago
10

G(x)= 8x+2 g(?) = -62

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
6 0
The answer is x= -8.
daser333 [38]3 years ago
6 0

Answer:

x = -8

Step-by-step explanation:

g(x)= 8x+2

Let g(x) = -62

-62 = 8x+2

Subtract 2 from each side

-62-2 = 8x+2-2

-64 = 8x

Divide each side by 8

-64/8 = 8x/8

-8 = x

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Find the area cut out of the cylinder x2 z2=9 by the cylinder x2 y2=9.
Digiron [165]
The cylinder is symmetric across the plane y=0, so we need only consider half of the cut-out region.

This region can be parameterized by

\mathbf r(r,\theta)=(r\cos\theta,\sqrt{9-r^2\cos^2t},r\sin\theta)

with 0\le\theta\le2\pi and 0\le r\le3. Then the area of this half is given by the surface integral

\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\left\|\mathbf r_r\times\mathbf r_\theta\right\|\,\mathrm dr\,\mathrm d\theta
=\displaystyle\int_0^{2\pi}\int_0^3\frac{3r}{\sqrt{9-r^2\cos^2\theta}}\,\mathrm dr\,\mathrm d\theta
=36

Doubling this gives a total area of 72.
6 0
3 years ago
I HAVE LOTS OF POINTS COMING FOR THE END OF ALL MY QUESTIONS SO PLEASE HELP OUT
Irina18 [472]

Answer:

1/5

Step-by-step explanation:

I think you go to the number 1 on the bottom and you go up 5 and there's your answer?

7 0
3 years ago
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Nate starts a lawn-mowing business. In his business, he has expenses and revenue. Nate's expenses are the cost of the lawn mower
Korolek [52]

The question is incomplete. The complete question is :

Nate starts a lawn-mowing business. In his business, he has expenses and revenue. Nate's expenses are the cost of the lawn mower and gas, and his revenue is $25 per lawn. At what point will Nate's revenue exceed his expense?

Cost of lawn mower = $ 200

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Solution :

Given :

Cost of the lawn mower = $ 200

The cost of gasoline expense for one lawn = $ 2

The revenue generated for one lawn = $ 25

So let the number of lawn to be mowed = x

Therefore the total expenses = $200+2x$

So, the total revenue = $25x$

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$25x \geq 200+2x$

So at x=9,  \ 225 > 218

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8 0
3 years ago
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Round off 1.0246 to 1 decimal to decimal 2 decimal
Anettt [7]

Answer:

1.0

Step-by-step explanation:

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3 years ago
What is the equation of the quadratic graph with a focus of (3, −1) and a directrix of y = 1?
Tomtit [17]
Use our brains and what we know
f(x)=a(x-h)²+k
vetex is (h,k)
and a is te leading coefient

if directix is below the focus, then it opens up and a is positive
if directix is above focus, then it opens down and a is negaitve

vertex is in between directix and focus


so
(3,-1) and y=1
-1<1
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directly in between
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vertex is (3,0)

y=a(x-3)²+0
y=a(x-3)²


the only option with a negative 'a' value is B

answer is B
5 0
3 years ago
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