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Vedmedyk [2.9K]
3 years ago
10

I HAVE LOTS OF POINTS COMING FOR THE END OF ALL MY QUESTIONS SO PLEASE HELP OUT

Mathematics
2 answers:
Irina18 [472]3 years ago
7 0

Answer:

1/5

Step-by-step explanation:

I think you go to the number 1 on the bottom and you go up 5 and there's your answer?

Jobisdone [24]3 years ago
3 0

Answer:

im not sure i suck at those problems

Step-by-step explanation:

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Solve for x. any help would be appreciated thanks
WARRIOR [948]
The correct answer is x=5

8 0
3 years ago
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What is the average rate of change over the interval (-1, 5)​
MArishka [77]

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete as the function is not given. However, the following explanation will guide you.</em>

<em></em>

The average rate of change is calculated using;

A = \frac{f(b) - f(a)}{b - a}

Where

(a,b) = (-1,5)

Take for instance;

The function is:

f(x) = 2x

We have to solve for f(-1) and f(5);

i.e.

f(-1) = 2 * -1  -2

f(5) = 2 * 5 = 10

Substitute -1 for a and 5 for b

A = \frac{f(b) - f(a)}{b - a}

A = \frac{f(5) - f(-1)}{5 - (-1)}

A = \frac{f(5) - f(-1)}{5 +1)}

A = \frac{f(5) - f(-1)}{6}

Substitute values for f(5) and f(-1)

A = \frac{10 - (-2)}{6}

A = \frac{10 +2}{6}

A = \frac{12}{6}

A = 2

<em>Apply this steps in your work</em>

5 0
3 years ago
A cyclist rides her bike at a speed of 10 kilometers per hour. What is this speed in miles per hour? How many miles will the cyc
SashulF [63]
6.25 miles per hour
12.5 miles in 2 hours
6 0
3 years ago
A penny is 1.9 cm wide. What is the circumference of a penny? Approximate using Pi = 3.14 and round the answer to the nearest te
Goshia [24]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards
katovenus [111]

Answer:

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

v=t^2-5t+4 ,\, t\geq0

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.

And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

v

By substitution:

t^2-5t+4

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

(t-4)(t-1)=0

Zero Product Property:

t=1, \text{ and } t=4

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

v(0)=4>0,\, v(2)=-20

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0
3 years ago
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