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dezoksy [38]
3 years ago
14

Find the measure of angle ACE.Arc AB is 100 degrees,Arc AE is 120 degrees, and Arc De is 100 degrees.

Mathematics
1 answer:
Olenka [21]3 years ago
3 0

Answer:

60 degrees

Step-by-step explanation:

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Estimate 25,953 to the nearest number
weeeeeb [17]
The answer is 26,000.
6 0
3 years ago
4s - 13 = 51 SHOW ALL WORK
RSB [31]

Answer:

you have to get rid of the numbers and then get rid of the letters until only s is left

Step-by-step explanation:

4s - 13= 51

51+13= 64

4s= 64

64÷4 = 16

s= 16

4 0
3 years ago
Sam walks from home to his school which is 0.75 miles away in 12 minutes. How fast was he walking?
SCORPION-xisa [38]

Answer:

<em>v = 3.75 mph</em>

Step-by-step explanation:

<u>Constant speed motion </u>

An object travels at a constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

Where  

v = Speed of the object

d = Distance traveled

t = Time taken to travel d.

Sam walks from home to school for a distance of d=0.75 miles in t=12 minutes. To calculate the speed, we need to convert the time to hours.

t=12/60 = 0.2 hours. Now compute the speed:

\displaystyle v=\frac{0.75\ mi}{0.2 \ h}

v = 3.75 mph

6 0
3 years ago
The marketing director of a large department store wants to estimate the average number of customers who enter the store every f
Dahasolnce [82]

Answer:

36.5674\leq x'\leq61.4326

Step-by-step explanation:

If we assume that the number of arrivals is normally distributed and we don't know the population standard deviation, we can calculated a 95% confidence interval to estimate the mean value as:

x-t_{\alpha /2}\frac{s}{\sqrt{n} } \leq x'\leq x-t_{\alpha /2}\frac{s}{\sqrt{n} }

where x' is the population mean value, x is the sample mean value, s is the sample standard deviation, n is the size of the sample, \alpha is equal to 0.05 (it is calculated as: 1 - 0.95) and  t_{\alpha /2} is the t value with n-1 degrees of freedom that let a probability of \alpha/2 on the right tail.

So, replacing the mean of the sample by 49, the standard deviation of the sample by 17.38, n by 10 and t_{\alpha /2} by 2.2621 we get:

49-2.2621\frac{17.38}{\sqrt{10} } \leq x'\leq 49+2.2621\frac{17.38}{\sqrt{10} }\\49-12.4326\leq x'\leq 49+12.4326\\36.5674\leq x'\leq61.4326

Finally, the interval values that she get is:

36.5674\leq x'\leq61.4326

8 0
3 years ago
Graph the system:<br> F(x)= 3/x-2; f(x)= 1/2x + 2
Makovka662 [10]

Answer:

We have the functions,

F(x)=\frac{3}{x-2} and f(x)=\frac{1}{2}x+2.

After plotting both the functions, we see that,

The graph of F(x) is given below, which has the y-intercept at (0,-1.5) and its horizontal asymptote is x-axis.

Also, the graph of f(x) is a straight line passing through (-4,0) and (0,2).

Further, we can see that the two graphs have intersection points as (-4.873,-0.436) and (2.873,3.436).

4 0
3 years ago
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