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Crank
3 years ago
14

M is the midpoint of AB, AM=3x+3 and AB=8x-6 What is the length of MB

Mathematics
1 answer:
Xelga [282]3 years ago
8 0
If it's the midpoint then MB=3x+3, but to find length set AM equal to one half AB
3x+3=(8x-6)(1/2) or 2(3x+3)=8x-6

2(3x+3)=8x-6
6x+6=8x-6
12=2x
X=6
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The area of a rectangular dining room is 16 square meters. The perimeter is 16 meters. What are the dimensions of the dining roo
neonofarm [45]

Answer:

4

Step-by-step explanation:

The area is 16, and you know that it's 2 sides u need to multiply

The perimeter is 16, and you know that you need to add up all the sides

So....

A = b * h

A = 4 * 4

A = 16    CORRECT

And....

P = S + S + S + S                                                         ( s = sides)

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6 0
3 years ago
Divede decimals by a whole number in this question 3.9÷3​
IgorC [24]

Answer:

The answer is 1.3, 1 3/10

4 0
2 years ago
Read 2 more answers
HELP PLS CLICK TO SEE THE QUESTION!!!
Maslowich

Answer:

3 1/4

Step-by-step explanation:

1) Convert 6 1/2 into a fraction and add it to 1/2.

6 -> 12/2

12/2 + 1/2 = 13/2

2) Divide the result by 2 (or multiple the result by the reciprocal of 2)

13/2 x 1/2 = 13/4 or 3 1/4

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5 0
3 years ago
Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180
torisob [31]

I got

-  \frac{6 3}{65}

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

\cos(a - b)  =  \cos(a)  \cos(b)  +  \sin(a)  \sin(b)

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

.

{12}^{2}  +  {y}^{2}  =  {13}^{2}

144 +  {y}^{2}  = 169

25 =  {y}^{2}

y = 5

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

.

( - 3) {}^{2}  +  {x}^{2}  =  {5}^{2}

9 +  {x}^{2}  = 25

{x}^{2}  = 16

x = 4

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

-  \frac{3}{5}  \times  \frac{5}{13}  +   - \frac {4}{5}  \times  \frac{12}{13}

- \frac{15}{65} + (  - \frac{48}{65}  )

-  \frac{63}{65}

Hope this helps

6 0
2 years ago
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