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gtnhenbr [62]
3 years ago
8

A phone company offers two monthly plans. Plan A costs $23 plus an additional $0.12 for each minute of calls. Plan B costs $18 p

lus an additional $0.14 of each minute of calls.
Mathematics
1 answer:
Alona [7]3 years ago
5 0

Answer:

250 minutes of calling will cost same using both plans.

$53

Step-by-step explanation:

Please consider the complete question.

A phone company offers two monthly plans. Plan A costs $23 plus an additional $0.12 for each minute of calls. Plan B costs $18 plus an additional $0.14 of each minute of calls.  For what amount of calling do the two plans cost the same?  What is the cost when the two plans cost the same?

Let x represent the number of call minutes.

The total cost of calling for x minutes using plan A would be cost of x minutes plus fixed charge that is 0.12x+23.

The total cost of calling for x minutes using plan B would be cost of x minutes plus fixed charge that is 0.14x+18.

To find the number of minutes for which both plans will have same cost, we will equate total cost of x minutes for both plans and solve for x.

0.14x+18=0.12x+23

0.14x-0.12x+18=0.12x-0.12x+23

0.02x+18=23

0.02x+18-18=23-18

0.02x=5

\frac{0.02x}{0.02}=\frac{5}{0.02}

x=250

Therefore, calling for 250 minutes will cost same using both plans.

Upon substituting x=250 in expression 0.14x+18, we will get:

0.14(250)+18=35+18=53

Therefore, the cost will be $53, when the two plans cost the same.

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HACTEHA [7]

Given:

The expression is

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To find:

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Solution:

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2\dfrac{1}{3}-1\dfrac{2}{5}=(2+\dfrac{5}{15})-(1+\dfrac{6}{15})

2\dfrac{1}{3}-1\dfrac{2}{5}=2+\dfrac{5}{15}-1-\dfrac{6}{15}

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