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3 years ago

14

Find the slope of a linear function passes through the points (3,2) and (-4,1)

1 answer:

Rzqust [24]3 years ago

3 0

Answer:

1/7

Step-by-step explanation:

We can use the slope formula(k=y₁-y₂/x₁-x₂) to solve this problem

k = 2-1/3-(-4) = 1/7

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Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago

A bag of pecans costs $3.84. If

Stels [109]

Answer:

10.4 cents

Step-by-step explanation:

40 pecans/$3.84 gives you pecans per dollar

6 0

4 years ago

An apartment building has the following apartments:

artcher [175]

On the second floor we have 6 apartments, and we have 2 more apartments with 3 bedrooms, so 8/16 apartments are either on the second floor or have 3 bedrooms. 8/16 is the same as 1/2, or 50%

3 0

3 years ago

Select the correct answer.

svp [43]

Step-by-step explanation:

option B is correct as,

10 + x = -18

→ x = -18 -10

→ x = -28

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3 0

3 years ago

Read 2 more answers

Due to conservation efforts, the gray whale has been removed from the endangered species list. There are now 13,000 in the world

brilliants [131]

Answer:

$P = 13,000(1.11) ^ t$

Step-by-step explanation:

This scenario can be modeled using an exponential growth equation.

The exponential growth equations have the following form:

$P = p (1 + r) ^ t$

Where P is the population in year t

p is the initial population at t = 0

r is the growth rate

t is the time in years.

In this case we know that the current population is 13,000 and that the growth rate is 11%

So

$p = 13,000\\r = 0.11$

The equation that models this scenario is:

$P = 13,000(1 + 0.11) ^ t$

$P = 13,000(1.11) ^ t$

4 0

3 years ago